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tia_tia [17]
3 years ago
10

What is 2 3/8 * 1/3. Estimate the product

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0
2 3/8 x 1/3 I believe? First you need to change 2 into a 16 then add that into 3 which is 19/8. You multiply across with 1/3 like with numerator with numerator and denominator with denominator. That then equals:19/24. You can't estimate it because 19 is a prime number.
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1. Estimate the area of the irregular shape. Explain your method and show your work.
wlad13 [49]

Answer:

31 square units

Step-by-step explanation:

See the picture below.

Each full or almost full square was counted first. There are 24 of them.

Then parts of squares of counted together to add to 1 square. They are color coded in the figure below. After adding them all up, the total was 31.

6 0
3 years ago
RS=2x-8, ST = 11, RT = x+10
ziro4ka [17]

Answer:

Equation~=~\Large\boxed{2x+3=x+10}

x~=~\Large\boxed{7}

RS~=~\Large\boxed{6}

RT~=~\Large\boxed{17}

Step-by-step explanation:

<u>Given information</u>

RS=2x-8

ST=11

RT=x+10

<u>Derived expression from the given information</u>

<em>Presumably, I think this is a combination of segments</em>

RS+ST=RT

<u>Substitute values into the given expression</u>

(2x-8)+(11)=(x+10)

<u>Combine like terms</u>

<em>The following is the expression</em>

\Large\boxed{2x+3=x+10}

<u>Subtract 3 on both sides</u>

2x+3-3=x+10-3

2x=x+7

<u>Subtract x on both sides</u>

2x-x=x+7-x

\Large\boxed{x=7}

<u>Substitute the x value into corresponding expressions to determine the final value</u>

RS=2x-8=2(7)-8=14-8=\Large\boxed{6}

RT=x+10=(7)+10=\Large\boxed{17}

Hope this helps!! :)

Please let me know if you have any questions

3 0
2 years ago
. 1. A consistent system of equations is a system with __________.. . the same line. . parallel lines. . intersecting lines and
madreJ [45]

A consistent system of equations is a system with intersecting lines and lines that have the same equation.

A consistent system is the system of equations with at least one solution or infinite number of solutions.

So , the intersecting lines will always have a solution and the lines with the same equation will have infinite number of solution.

The graph of a system of equations with different slopes will have no solutions. Correct option in "Never"

If the system of equations have different slopes then the equations are not parallel, hence the equations will always have a solution.

3 0
3 years ago
If X = 4 units, Y = 3 units, and Z = 10 units, then what is the volume of the triangular pyramid shown above?
Levart [38]

Answer:

40

Step-by-step explanation:

5 0
2 years ago
A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0
2 years ago
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