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denpristay [2]
2 years ago
5

(HELP!)Coach DeCaro records the cross country runners' times compared to their personal best times. Which runners ran slower tha

n their personal best?

Mathematics
2 answers:
Akimi4 [234]2 years ago
7 0

Answer:

D Is the answer.

Step-by-step explanation:

Good Luck uWu

Alborosie2 years ago
6 0

Answer:

it should be karen and hiroki

karen ran 5.2 seconds slower than her personal best

hiroki ran 11.6 slower than his/her best

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The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
How do you simplify 16^2/24^7
quester [9]

Answer:

1/(2¹³·3⁷)

Step-by-step explanation:

                                                16²/24⁷

Factor the terms                  = (2⁴)²/(8×3)⁷

Apply the Power Rule        = 2⁸/(2³×3)⁷

Apply the Power Rule        = 2⁸/(2²¹ × 3⁷)

Apply the Quotient Rule    = 1/(2¹³·3⁷)

5 0
3 years ago
If you add my number to it's self and add 83 you will get the same number as when you add my number 4 times and subtract 25
Deffense [45]
I think you should put in 53 try that 

7 0
3 years ago
Find the base of a traingle with area 20dm² and height 12 1/2dm <br>​
AlexFokin [52]

9514 1404 393

Answer:

  32 dm

Step-by-step explanation:

Use the formula for the area of a triangle, and solve for the unknown.

  A = 1/2bh

  200 dm² = 1/2(12.5 dm)b

  b = (200 dm²)/(6.25 dm) = 32 dm

The base of the triangle is 32 dm.

3 0
2 years ago
En tres partidos de besisbol de fin de Semana, hubo 125,429 espectadores .La Semana siguiente hubi 86,353 especradores cuantos e
Pavlova-9 [17]

Answer:

211,782

Step-by-step explanation:

Esta pregunta es muy fácil porque Los espectadores en total que presenciaron los seis partidos en total es la suma de ambos.

125,429 en uno lado y 86,353 en uno lado. Y eso es igual

125,429 + 86,353 = 211,782

Los espectadores en total que presenciaron los seis partidos en total es 211,782

8 0
2 years ago
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