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3 years ago

Sales fall from 300 per week to 270 per week what’s the percentage change

1 answer:

8 0

Hi there!

Your question:

Sales fall from 300 per week to 270 per week what's the percentage change?

My answer:

The formula for calculating percent change is as follows:

[(y2 - y1)/y1]*100=your percent change

y2= first value
y1=second value

Plug the numbers in:

[(300-270)/300]*100

[30/300]*100

0.1*100

10

Therefore, the percent change is 10%

Hope this helps! Let me know if it's incorrect so I can fix it:)

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Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th

Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

$d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0$

5 0

3 years ago

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Marymount Township secured the construction of a power plant, which opened in 1990. Once the power plant opened

Aleksandr [31]

Answer:

92087,14873

Step-by-step explanation:

Given that Marymount Township secured the construction of a power plant, which opened in 1990. Once the power plant opened in 1990, the population of Marymount increased by about 20% each year for the first ten years and then increased by 5% each year after that

Let P0 be the population in 1990

Then we have in 2000 the population is

$P(2000) = P_0(1.2)^{10}$

with this initial population for next growth we have in 2010 the population would be

$P(1.05)^{10}$ , where P = population is 2000

a) Given that $P(1.05)^{10) = 150000\\P = 150000(1.05)^{-10} =92.086.99\\=92087$

b) we use the exponential equation and solve for initial population in 2000.

c) we have

$P_0(1.2)^{10} =92087\\P_0 = 92087((1.2)^{-10})\\=14872.56\\=14873$

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3 years ago

A) If Pablo drove at an average speed of 85 km/h for 3.75 h, what distance did he drive?

zhannawk [14.2K]

Answer: 19

Step-by-step explanation:

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3 years ago

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Olin [163]

Answer:

$- 2$

Step-by-step explanation:

2^2×2^3(x+1)=2^2x

same base cancel,you will get

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$x = - 2$

4 0

3 years ago

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Mr. Williams is building a sand box for his children. It costs $228 for the sand if he builds a rectangular-sand box with dimens

Andru [333]

Answer: The correct option is (C) $342.

Step-by-step explanation: Given that Mr. Williams is building a sand box for his children and is costs $228 for the sand if he builds a rectangular-sand box with dimensions 9 ft by 6 ft.

We are to find the cost of the sand if he decides to increase the size to $13\frac{1}{2}~\textup{ft by }9~\textup{ft}.$

Since the box is empty from inside, so we will be considering the perimeter of the box, not area.

The perimeter of the rectangular-sand box with dimensions 9 ft by 6 ft is

$P_1=2(9+6)=30~\textup{ft},$

and the perimeter of the rectangular-sand box with dimensions $13\frac{1}{2}~\textup{ft by }9~\textup{ft}.$ is

$P_2=2\left(13\dfrac{1}{2}\times9\right)=2(13.5\times9)=45~\textup{ft}.$

Now, we will be using the UNITARY method.

Cost of sand for building rectangular-sand box with perimeter 30ft = $228.

So, cost of sand for building rectangular-sand box with perimeter 1 ft will be

$\$\dfrac{228}{30}.$

Therefore, the cost of sand for building rectangular-sand box with perimeter 45 ft is given by

$\$\dfrac{228}{30}\times45=\$342.$

Thus, the required cost of the sand is $342.

Option (C) is CORRECT.

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3 years ago

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