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3 years ago

Really easy for high schoolers (The first correct answer gets brainliest! )

Mathematics

1 answer:

Arturiano [62]3 years ago

8 0

Answer:-18

Términos en este conjunto (8)

Original

El Swing encarna el espíritu de la Revolución Francesa.

falso

El Swing fue un éxito inmediato debido a su brillantez técnica y al escándalo detrás de él.

cierto

Las pinturas de Jean-Honoré Fragonard tratan temas religiosos serios.

falso

Las pinturas Marriage A-la-Mode de Hogarth corresponden y, en ocasiones, evocan deliberadamente el arte francés y el diseño rococó.

cierto

En la serie Marriage A-la-Mode de Hogarth, Lord Squanderfield es robusto y saludable.

falso

Step-by-step explanation:

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What is the fourth term in the sequence given by a n=5n+3

OverLord2011 [107]

To determine the fourth term, plug 4 into the equation;
$n = 5n+3 \\ n_{4} =5(4)+3 \\ n_{4} =20+3 \\ n_{4}=23$

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3 years ago

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Sholpan [36]

Answer:

18.78

Step-by-step explanation:

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x=18.78

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3 years ago

Can you help me on question 17

Orlov [11]

Answer:

57 + x³

Step-by-step explanation:

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3 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$