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3241004551 [841]
3 years ago
13

There was a 6 square-foot pieces of wrapping paper for a present.It takes 3 1/8 square feet of paper to wrap the present.How man

y pieces of a 6-foot-square paper are needed to wrap 2 presents.
Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

The answer to your question is: 2 pieces of paper.

Step-by-step explanation:

Data

6 ft²

1 present = 3 1/8 ft²

Process

Get the result of adding the area needed to wrap to presents.

                3 1/8 + 3 1/8 = 6 2/8  = 6 1/4               Remember to add the

                                                                             whole numbers and the

                                                                             fractions independently.

Each paper measures 6 ft² and we need to wrap two presents 6 1/4 ft², so we need to pieces of paper to wrap the presents.

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When decreases in one variable are accompanied by decreases in another variable, the variables are described as?
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Directly proportional or positively correlated
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3 years ago
A bank made a farmer loan of $1,000 at 14% for 3 years compounded annually. Find the future value and the compound interest paid
Anna11 [10]

Answer:

Principal =  $1,000

Rate of interest = 14% = 0.14

Time = 3 years

A= P(1+r)^t

A = Amount or future value

P = Principal

r = rate of interest in decimals

t = time

Substitute the values in the formula

A= 1000(1+0.14)^3

A=1481.544

Future Value is $1481.544

Compound interest = Amount - Principal = $1481.544- $1000 = $481.544

Formula of simple interest : SI =\frac{P \times R \times T}{100}

Substitute the values :

SI =\frac{1000 \times 14 \times 3}{100}

SI =420

So, Simple interest = $420

Compound interest - Simple interest

= $481.544- $420

= $61.544

So, Compound Interest is $61.544 more than simple interest.

8 0
3 years ago
A composite shape is shown.
kodGreya [7K]

Answer:

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Step-by-step explanation:

Have a good day

3 0
3 years ago
Read 2 more answers
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Alex Ar [27]

Answer: The answer is A.

Step-by-step explanation:

4 0
2 years ago
The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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