Answer:
$150
Step-by-step explanation:
25x4=100
100+50=150
so she has $50 to spend on other things
i dont know if this is what its asking or how
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
TERO BAU KO TAUKO MULA JEPAITE SODCHOS
Answer:
b= (Z-m-z)/(x)
Step-by-step explanation:
Z-m=z+bx
Z-m-z=bx [Transpose z of R.H.S to L.H.S] / [Substract z from L.H.S and R.H.S]
(Z-m-z)/(x)=b [Divide by x on both sides i.e, L.H.S and R.H.S]
b= (Z-m-z)/(x)
Hope this helps you.
I've attached the graphs to this answer. I hope they help.
