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kicyunya [14]
3 years ago
11

Which of the following is the graph of the quadratic function y= x2 - 4x + 4

Mathematics
1 answer:
olganol [36]3 years ago
7 0

Answer:

graph c

Step-by-step explanation:

it is the longest one

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7 1/6 divided by 5/9
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Kiran jogs at a speed of 6 miles per hour when there are no hills. He plans to jog up a mountain road, which will cause his
Sergio [31]

Answer:

The equation is t = \frac{8}{6 - r}

Step-by-step explanation:

First off, we know r is going to be subtracted from 6 somewhere in the expression since the problem says "decreasing by r miles per hour."

If we want to see how long it would take him to jog 8 miles up to the mountain road we would have to take 8 and divide it by 6 - r.

Therefore, the equation is t = \frac{8}{6 - r}

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8 0
3 years ago
PLS HELP WITH THE QUESTION IN THE PICTURE!!!
Ksivusya [100]

Answer:

D

Step-by-step explanation:

Interesting question.  The wording is a bit awkward. I think you have to assume the base is a square and each succeeding base is also a square.

So the first thing to do is to add the bases together.

30*30 + 23*23 + 16*16 + 9*9

Don't add these -- not yet.

Now take the height into consideration

6 *(30*30 + 23*23 + 16*16 + 9*9)

The point is that you only have to multiply by 6 once.

6*(900 +  529 + 256 + 81)

6*(1766)

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5 0
3 years ago
A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place
Andrej [43]

Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

P(t) = P(0)(1-r)^{t}

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

P(1) = 0.97P(0)

Then

P(t) = P(0)(1-r)^{t}

0.97P(0) = P(0)(1-r)^{0}

1 - r = 0.97

So

P(t) = P(0)(0.97t)^{t}

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

P(t) = P(0)(0.97t)^{t}

0.5P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.5

\log{(0.97)^{t}} = \log{0.5}

t\log{0.97} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.97}}

t = 22.76

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

P(t) = P(0)(0.97t)^{t}

0.85P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.85

\log{(0.97)^{t}} = \log{0.85}

t\log{0.97} = \log{0.85}

t = \frac{\log{0.85}}{\log{0.97}}

t = 5.34

5.34 years for the sample to decay to 85% of its original amount

8 0
4 years ago
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