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vladimir2022 [97]

3 years ago

10

Help this is high school mathematics and even though I’m usually good I need a little help it would be nice if you could also pr

ovide how you found the answer
Thank you :)))

1 answer:

Kitty [74]3 years ago

7 0

Step-by-step explanation:

I'm not sure if this correct or not

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Solve this by substitution

frozen [14]

Answer:

y= 1 and x=-2

Step-by-step explanation:

Since they both equal y, you can equal them to each other:

x + 3 = 2x + 5

Then solve:

x - x + 3 = 2x - x + 5

3 - 5 = x + 5 - 5

-2 = x

Substitute x in either equation to solve for y:

y = (-2) +3

y = 1

Or the other equation:

y = 2(-2) + 5

y = -4 + 5

y = 1

hope this helps :)

6 0

2 years ago

Describe the transformation that maps the pre image A to the image A'

Leya [2.2K]

Answer:

B) translated 6 units to the right then translated 9 units up

Step-by-step explanation:

Just use the graph to follow each translation until you get thee right answer, or you can count how many spaces are from the pre-image to the image. Just make sure to always use the same point.

4 0

3 years ago

Read 2 more answers

Answer with explanation plz

Nostrana [21]

The answer is 78.5 because the formula to find area is πr2 so the radius is 5ft π is 3.14 so 3.14 times 5 and the 2 on top of r means the u have to do 5 times 5 which is 25 now it's real simple do 3.14 times 25 which is 78.5 I HOPE THIS HELPS=)

7 0

2 years ago

I dont understand this

kirza4 [7]

Step-by-step explanation:

first u find the angles and then u use some low divide the length of triangle by sin of opposite angles

4 0

3 years ago

Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago