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Marianna [84]
3 years ago
12

I TRIED SO MANY THINGS AND I JUST DO NOT UNDERSTAND WHAT I AM DOING, CAN I PLEASE GET SOME HELP QUICK. ITS SOLVING ALL SOLUTIONS

FOR X.
I included a image please someone help I need help with my homework.

Mathematics
1 answer:
monitta3 years ago
3 0

8. \:  \:  \:  \: 2 {x}^{2}  + 14 = 22 \\  \\  =  > 2 {x}^{2}  = 22 - 14 \\  \\  =  > 2 {x}^{2}  = 8  \\  \\  =  >  {x}^{2}  =  \frac{8}{2}  \\  \\  =  >  {x}^{2}  = 4 \\  \\  =  > x =  \underline{+}\sqrt{4}  \\  \\  =  >  \green {\boxed{x = 2\: or \: (-2)}} \\  \\  \\  \\  \\ 9. \:  \:  \:  \: 8 {x}^{2}   +  19 = 54 + 3  {x}^{2}  \\  \\  =  > 8 {x}^{2}  - 3 {x}^{2}  = 54 - 19 \\  \\  =  > 5 {x}^{2}  = 35 \\  \\  =  >  {x}^{2}  =  \frac{35}{5}  \\  \\  =  >  {x}^{2}  = 7 \\  \\  =  > x =    \underline{ + } \sqrt{7}  \\  \\ =  >  \green{\boxed{ x =  \sqrt{7}  \: or \: ( -  \sqrt{7} )}}\\\\\\\\10. \:  \:  \: 7 {x}^{2}  + 12 = 51 - 4 {x}^{2}  \\  \\  =  > 7 {x}^{2}  + 4 {x}^{2}  = 51 - 12 \\  \\  =  >  11 {x}^{2}  = 39 \\  \\  =  >  {x}^{2}  =  \frac{39}{11}  \\  \\  =  >  {x} =      \underline{+ }\sqrt{ \frac{39}{11} }  \\  \\  =  >  \green{\boxed{ x =  \sqrt{ \frac{39}{11} }  \: or \:  (-  \sqrt{ \frac{39}{11} } )}}

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Answer:

y=120,000(1.055)^x

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

y=a(1+r)^x

where

y is the value of the home

x is the number of years

a is the initial value

r is the rate of change

we have

a=\$120,000\\r=5.5\%=5.5/100=0.055

substitute

y=120,000(1+0.055)^x

y=120,000(1.055)^x

7 0
3 years ago
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aksik [14]

Answer:

QR=8

QU=76

Measure of arc ST=114°

Measure of arc QR=114°

Measure of arc XT=57°

Step-by-step explanation:

Given

YU=YV

ST=16

mQS=34

mRT=98

Using Pythagoras theorem,

QR=8

QU=76

QR=ST

So they both span the same arc.

Let the arc=x

360 - QS - RT = QR + ST

Recall QR=ST

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228 = 2x

X=228/2

X=114°

Therefore, measure of arc ST and arc QR=114° each

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dalvyx [7]

Answer:

+65=-30x-5x^2

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egoroff_w [7]

Answer:

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Step-by-step explanation:

4 0
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