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Marianna [84]
2 years ago
12

I TRIED SO MANY THINGS AND I JUST DO NOT UNDERSTAND WHAT I AM DOING, CAN I PLEASE GET SOME HELP QUICK. ITS SOLVING ALL SOLUTIONS

FOR X.
I included a image please someone help I need help with my homework.

Mathematics
1 answer:
monitta2 years ago
3 0

8. \:  \:  \:  \: 2 {x}^{2}  + 14 = 22 \\  \\  =  > 2 {x}^{2}  = 22 - 14 \\  \\  =  > 2 {x}^{2}  = 8  \\  \\  =  >  {x}^{2}  =  \frac{8}{2}  \\  \\  =  >  {x}^{2}  = 4 \\  \\  =  > x =  \underline{+}\sqrt{4}  \\  \\  =  >  \green {\boxed{x = 2\: or \: (-2)}} \\  \\  \\  \\  \\ 9. \:  \:  \:  \: 8 {x}^{2}   +  19 = 54 + 3  {x}^{2}  \\  \\  =  > 8 {x}^{2}  - 3 {x}^{2}  = 54 - 19 \\  \\  =  > 5 {x}^{2}  = 35 \\  \\  =  >  {x}^{2}  =  \frac{35}{5}  \\  \\  =  >  {x}^{2}  = 7 \\  \\  =  > x =    \underline{ + } \sqrt{7}  \\  \\ =  >  \green{\boxed{ x =  \sqrt{7}  \: or \: ( -  \sqrt{7} )}}\\\\\\\\10. \:  \:  \: 7 {x}^{2}  + 12 = 51 - 4 {x}^{2}  \\  \\  =  > 7 {x}^{2}  + 4 {x}^{2}  = 51 - 12 \\  \\  =  >  11 {x}^{2}  = 39 \\  \\  =  >  {x}^{2}  =  \frac{39}{11}  \\  \\  =  >  {x} =      \underline{+ }\sqrt{ \frac{39}{11} }  \\  \\  =  >  \green{\boxed{ x =  \sqrt{ \frac{39}{11} }  \: or \:  (-  \sqrt{ \frac{39}{11} } )}}

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HELP SOS IMMEDIATELY THANK YOUUUUU!!!!
e-lub [12.9K]

Answer:  b) 18.37

<u>Step-by-step explanation:</u>

Since the intial t-value is 1960 and the final t-value is 1990, then t = 30

P(30)=\dfrac{100}{1+400\cdot e^{-0.15(30)}}\\\\\\.\quad =\dfrac{100}{1+400\cdot e^{-4.5}}\\\\\\.\quad =\dfrac{100}{1+400(0.0111)}}\\\\\\.\quad =\dfrac{100}{1+4.4436}}\\\\\\.\quad =\dfrac{100}{5.4436}}\\\\\\.\quad =\boxed{18.37}

4 0
2 years ago
Complete the square 2m2−3m=−50
rusak2 [61]

Answer:

Completing the square answer

\left(m  - \frac{3}{4}\right)^2 =  - \frac{391}{16}

Solution set

m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4} = 0.75 + 4.94343 \, i

m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4} = 0.75 - 4.94343 \, i

Step-by-step explanation:

Assuming the question is correctly interpreted as 2m2 = 2m², here is how to proceed

We have 2m^2 - 3m =-50

Divide by 2 on both sides

m^2 - \frac{3}{2}m =  - 25

Take half of the  coefficient of x and square it

\left[  - \frac{3}{2} \cdot \frac{1}{2} \right]^2 = \frac{9}{16}

Add the result to both sides

m^2 - \frac{3}{2}m + \frac{9}{16} =  - 25 + \frac{9}{16}

m^2 - \frac{3}{2}m + \frac{9}{16} can be re-written as a perfect square

\left(m  - \frac{3}{4}\right)^2

The RHS becomes

- 25 + \frac{9}{16} = \frac{(-25)(16) + 9}{9} = \frac{-391}{16}

Therefore,

\left(m  - \frac{3}{4}\right)^2 =  - \frac{391}{16}

Take the square root of both side

m  - \frac{3}{4} = \pm \sqrt[]{ - \frac{391}{16}}

Simplify

m  - \frac{3}{4} = \pm \frac{\sqrt[]{391}i}{4}

Adding \frac{3}{4} both sides

m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4}

This gives the two solutions

m= \frac{3}{4} + \frac{\sqrt[]{391}i}{4}  and

m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}

which becomes

m = 0.75 + 4.94343 \, i and

m = 0.75 - 4.94343 \, i

4 0
1 year ago
Find the area of the rectangle with the given base and height. 7 ft, 4 in
masha68 [24]

Answer:

336 sq. in or 2.333333333 sq. ft.

Step-by-step explanation:

1 foot = 12 in

7 x 12 = 84 in

A = bh

A = 84 in x 4 in

A = 336 sq. in

1 sq. ft. = 144 sq. in

336 / 144 = 2.33333333 sq. ft.

7 0
3 years ago
3. ** Over the course of July, the high temperatures of 6 random days were collected. The data is 2 shown below. 84°F 92°F 79°F
Tresset [83]

Given data:

The given table.

The expression for the average temperature is,

\begin{gathered} 86^{\circ}F=\frac{84^{\circ}F+92^{\circ}F+79^{\circ}F+x+82^{\circ}F+93^{\circ}F}{6} \\ 516^{\circ}F=430^{\circ}F+x \\ x=86^{\circ}F \end{gathered}

Thus, the value of x is 86 degree Fahrenheit.

7 0
1 year ago
Please help me on this! my homework is hard :(
Marat540 [252]

Answer:

a

Step-by-step explanation:

8 0
2 years ago
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