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2 years ago

Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 ft

Mathematics

1 answer:

ad-work [718]2 years ago

7 0

Answer:Solution :-

Volume of the square pyramid = 12 cubic feet

Base length = 3 feet

We know that,

Volume of a square pyramid is (1/3) × (base area) × Height

⇒ 12 = (1/3) × (3*3) × Height

⇒ 12 = 9h/3

⇒ 9h = 12*3

⇒ 9h = 36

⇒ h = 36/9

⇒ Height = 4 feet

So, the height of the square pyramid is 4 feet.

PLEASE GIVE BRAINLIEST

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.

Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = $\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})$

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Diagonal 1 (AC) = $\sqrt{(4-0)^2+(-1+1)^2}$ = 4 units

Diagonal 2(BD) = $\sqrt{(2-2)^2+(3+5)^2}$ = 8 units

Now area of the rhombus ABCD = $\frac{1}{2}(\text{AC})(\text{BD})$

= $\frac{1}{2}\times 4\times 8$

= 16 units²

Therefore, area of the given rhombus is 16 units².

5 0

2 years ago

use symbols to compare the numbers 512 and 521. write the comparison to ways. then explain your thinking

Morgarella [4.7K]

Solution:- Given numbers to compare are 512 and 521 .

As they are 3 digit numbers

So, we have to compare hundreds place.

But hundreds are equal in both the numbers with digit 5.

Next we have to compare tens place.

Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .

So we get the result that,

512 is smaller than 521

or <em> 512 < 521</em>

Case 2:-2 tens is greater in 521 than 1 ten in 512 .

So we get the result that,

521 is greater than 512

or <em> 521 > 512</em>

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3 years ago

HELP ME PLEASE SOMEONE!!

KiRa [710]

You have the correct answer being (-5,3). Simply add the parentheses around the point

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1 year ago

Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu

Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4 $a^{4}$ - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u² - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = $\frac{1}{4}$

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

a² = $\frac{1}{4}$ ⇒ a = ± $\frac{1}{2}$

Solutions are a = ± 1 , a = ± $\frac{1}{2}$

7 0

3 years ago

Linda buys a packet of biscuits, there were p biscuits in it. She eats y of them and gave the rest to her friend. How many biscu

Mkey [24]

She eats y out of the p

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2 years ago

Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 ft​

Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 ft