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RideAnS [48]
3 years ago
11

Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 ft​

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer:Solution :-

Volume of the square pyramid = 12 cubic feet

Base length = 3 feet

We know that,

Volume of a square pyramid is (1/3) × (base area) × Height

⇒ 12 = (1/3) × (3*3) × Height

⇒ 12 = 9h/3

⇒ 9h = 12*3

⇒ 9h = 36

⇒ h = 36/9

⇒ Height = 4 feet

So, the height of the square pyramid is 4 feet.

PLEASE GIVE BRAINLIEST

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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

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As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

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Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
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