C = kmt
k = C/mt
Units of k are Calories per pound - minute.
<h3><u><em>I</em></u><u><em>
nitial considerations</em></u></h3>
- <em>radius = 1.8 in</em>
- <em>tall = 6.7 in</em>
- <em>Volume?</em>
<h3><u><em>Resolution</em></u></h3>
<em>Volume = base area x tall</em>
<em>base area = π x (1.8in)²</em>
<em>base area = 10.179 in²</em>
<em>Volume = 10.179 in² x 6.7 in</em>
<em>Volume = 68.198 in³</em>
<h3 /><h3><em><u>Answer</u></em></h3>
<em>the volume is 68.198 in³</em>
What you do is just find the missing value of the x.

Differentiate both sides wrt
:

By the chain rule, we get


Solve for
:

