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alex41 [277]
4 years ago
5

Consider a firm handling concessions for a sporting event. The firm’s manager needs to know whether to stock up with coffee or col

a and is formulating policies for specific weather predictions. A local agreement restricts the firm to selling only one type of beverage. The firm estimates a $1500 profit selling cola if the weather is cold and a $5000 profit selling cola if the weather is warm. The firm also estimates a $4000 profit selling coffee if it is cold and a $1000 profit selling coffee if the weather is warm. The weather forecast says that there is a 30% of a cold front; otherwise, the weather will be warm. Build a decision tree to assist with the decision. What should the firm handling concessions do?

Mathematics
1 answer:
julsineya [31]4 years ago
5 0

Answer: Cola is more profitable over Coffee

Step-by-step explanation:

E(cola) = 0.3 * 1500 + 0.7 * 5000

E(cola) = 450 + 3500

E(cola) = 3950

E(coffee) = 0.3 * 4000 + 0.7 * 1000

E(coffee) = 1200 + 700

E(coffee) = 1900

From the decision tree which is attached, and the calculations above, it would be advised that the firm should focus on Cola, since it has a higher expected revenue of $3950, compared to the expected revenue of $1900 for coffee.

See the attached image for the decision tree

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4 years ago
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During a school event, there were 8 times as many pupils as teachers and there were three times as many boys as girls. There wer
Lilit [14]
We know that pupils are students

Students = S
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So....

S = 8T
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2 years ago
What is 2478 rounded to the nearest thousand​
Mariana [72]

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3 years ago
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Use Remainder Theorem to determine if x-2 is a factor of the polynomial f(x)=3x^5 - 7x^3 -
morpeh [17]

<u>Answer:</u>

(x - 2) is not a factor of f(x)  = 3x^5 - 7x^3 -  11x^2 + 2

<u>Step-by-step explanation:</u>

According to the Remainder Theorem, when a polynomial f(x) is divided by a term (x - r), then the remainder must be f(r).

So first we will divide f(x) by (x - 2) using long division to get:

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= 3x^4 + (6x^4 - 7x^3 - 11x^2 + 2) / (x-2)

= 3x^4 + 6x^3 + (5x^3-11x^2+2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 (-x^2 + 2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 -x -2 - (2) / (x -2)

= \frac{-2 + 3x^{5} - 7x^{3} - 11x^{2} + 2x}{x - 2} - 2

Therefore the remainder is -2.

Now check x = 2 for 3x^5 - 7x^3 -  11x^2 + 2:

3(2)^5 - 7(2)^3 -  11(2)^2 + 2 = -2

The Remainder Factor theorem also states that if (x - r) is a factor of f(x) then f(r) must be 0.

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3 years ago
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Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

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From the given statement:

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then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

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now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

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7 0
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