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mel-nik [20]
3 years ago
6

1.What is 1/3 of 3/2 ?can you guys help me​

Mathematics
2 answers:
Hunter-Best [27]3 years ago
5 0

Answer: 1/2

Step-by-step explanation: 1/2 times 3 is the improper fraction 3/2

hammer [34]3 years ago
5 0

Answer:

The answer is 1/2

Step-by-step explanation:

1/3 x 3/2

To break it up you multiply the top numbers to get 3

The you'd multiply the bottom numbers to get 6

so your answer is 3/6 which is also equal to 1/2

You might be interested in
-2/3- (-3/4)<br><br> Simplify if needed <br> Brainliest <br><br> Also, 5/6+5/12
bazaltina [42]

Answer:

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

Step-by-step explanation:

Given

-\frac{2}{3} - (-\frac{3}{4})

Required

Solve:

-\frac{2}{3} - (-\frac{3}{4})

Open bracket

-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}

Take LCM

-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12}

Take LCM

\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}

\frac{5}{6} + \frac{5}{12} = \frac{15}{12}

Divide by 3/3

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

4 0
3 years ago
Write and solve an equation based off the verbal phrase: 6 more than x is equal to 33
kenny6666 [7]

Answer:

x + 6 = 33

Step-by-step explanation:

6 more than x means there's an increment in the value of x by addition of 6

x + 6 = 33

This leads to an algebraic linear equation. x is an unknown variable and can be solved for

we subtract 6 from both sides of the equation

x + 6 - 6 = 33 - 6

x = 27

Therefore, we can say 6 more than 27 is 33

5 0
3 years ago
4, 11.6, 50, 23, 20.1, 19, 29, 12.7, 8, 23, 57.5 The min= The max- 015 Q2 Q3 The range The interquartile range​
earnstyle [38]
Ty for points ahaha












No jk lol I think it’s 12.7
4 0
2 years ago
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
2 years ago
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