Given :
On a coordinate plane,a curved line with 3 arcs, lab led f of x, crosses the x-axis at (negative 2,0), (negative 1,0), (1,0), and (3,0) and the y axis at (0, negative 6).
To find:
f when x = 0. i.e. f (0).
Solution:
since the graph has 3 arcs and 4 solutions, it can be visualized as the follows:
Between each solution, the function has to increase and decrease giving arcs in between.
1. One of the arcs is between (negative 2,0) and negative (1,0)
2. Second arc is between (negative 1,0) and (1,0)
-this arc cuts the y axis, since x= 0 lies between x= -1 & x=1-
3. Third arc is between (1,0) and (3,0)
Therefore only the 2nd arc cuts the y axis
It’s given that the curve cuts the y axis at (0, -6)
That is when x= 0, f(0) =-6
Therefore the value of f (0) is -6 only.
HOPED THIS HELPED LUV!!
Answer:
In these two parallelograms, the sides that are same are:
ST = WX
TU = XY
UV = YZ
SV = ZW
Therefore according to the question, the correct option is
d) ST = WX
If my answer helped, please mark me as the brainliest!!
Thank You!
Answer:
32
Step-by-step explanation:
Answer:
I would say not a function but im not 100% sure, i would go with not a function. Tell me if im wrong.
Step-by-step explanation:
Answer:
x = -3
Step-by-step explanation:
4x - 1 = -13
add 1 to each side
4x = -12
x = -3
