Method 1:

$\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}$

Method 2.

$\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}$

3 0

3 years ago

Determine the height of the can of beans(cylinder) given the volume of the

jeka94

Answer:

4 in(a)

Step-by-step explanation:

height-?

volume-314

radius-5

pie-22÷7 or 3.14

volume= πrsquared h

314=3.14×5×5×h

314= 78.5h

314÷78.5

= 4 in

8 0

2 years ago

HELP PLS !! WORTH 62 PTS !!!

kupik [55]

I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form

4 0

2 years ago

Read 2 more answers

​ E=6c 2−2c−1 F=−4c 2 +7c+5 E+F= ​

E=6c 2−2c−1 F=−4c 2 +7c+5 E+F=