3 consecutive integers for 273

Mathematics

1 answer:

a_sh-v [17]2 years ago

8 0

Answer:

90, 91 and 92

Step-by-step explanation:

Given

Consecutive integers = 273

Required

Find the integers

The question seem to be incomplete. However, I'll assume we're dealing with sum.

Let the smallest integer be y.

So,

y + y + 1 + y + 2 = 273

Collect like terms.

y + y + y = 273 - 2 - 1

3y = 270

Divide both sides by 3

y = 90

Hence, the integers are 90, 91 and 92

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