Answer:
Step-by-step explanation:
7 hours ago I gave you the answer on this question, my dear!!
Please help me solve this step by step ASAP please
1 answer:
You might be interested in
We have given three school there, School A, School B and School C.
We are going to use following formula.
Total number of student in a school = Mean of number of student × Number of classrooms.
School A
Mean of students in School A = 32.5.
Number of classroom in School A = 25.
Number of students in School A = Mean × number of classrooms = 32.5×25 = 812.5
School B
Mean of students in School B = 29.6.
Number of classroom in School B = 12.
Number of students in School B = Mean × number of classrooms = 29.6×12 = 355.2
School C
Mean of students in School C = 15.3.
Number of classroom in School C = 10.
Number of students in School C = Mean × number of classrooms = 15.3×10 = 153.
Total sum of number of classes in all schools = 25+12+10 = 47.
Total sum of all students in all schools = 812.5 +355.2 +153 = 1320.7 .
The mean number of students per classroom for all the schools combined =
= = 28.1
The mean number of students per classroom for all the schools combined= 28.1
The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
)
- R' = 8640/
- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315