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3 years ago

Please help me solve this step by step ASAP please

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

6 0

Y=130 hope this helps
Step by step:
If y =10 when x =4 then
y=130 when x= 52 because it it multiplied by 13 4*13=52 then 10*13=130

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Chapter 8: Chapter 8 Test > chapter Test

Vikentia [17]

Answer:

D = sqrt[ (2-4)^2 + (7- (-1))^2] = ~8.2

Step-by-step explanation:

D = sqrt[ (Fx-Gx)^2 + (Fy- Gy)^2]

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3 years ago

Hayden earns $9.50 per hour as a lifeguard.He earns a bonus of $50.00 for taking a training course.How many hours must he work t

mel-nik [20]

Answer: he must work for at least 26.32 hours

Step-by-step explanation:

Let x represent the number of hours that Hayden works as a life guard.

Hayden earns $9.50 per hour as a lifeguard. This means that the amount that he earns for working for x hours would be

9.5x

He earns a bonus of $50.00 for taking a training course. If he takes this bonus cost, the amount that he would earn for working for x hours is

9.5x + 50

Therefore, the number of hours that he must work to earn at least $300.00 would be

9.5x + 50 ≥ 300

9.5x ≥ 300 - 50

9.5x ≥ 250

x ≥ 250/9.5

x ≥ 26.32

4 0

3 years ago

The coordinates of the vertices of the triangle are (–8, 8), (–8, –4), and . Consider QR the base of the triangle. The measure o

Mademuasel [1]

The coordinates of the vertices of the triangle are
(–8, 8), (–8, –4), and (10, –4).

Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = 12 units.

The area of triangle PQR is108 square units.

4 0

3 years ago

Read 2 more answers

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$