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3 years ago

15

If A = { a, b, c, d} and B = {b,c,d,e} Then find AnB {b,c,d}

1 answer:

vladimir1956 [14]3 years ago

5 0

Answer:

AnB = ( b, c, d ) is the answer.

Hope this will help u

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6/1 x 7/4 in simplest form

dalvyx [7]

The answer would be 10.5 in decimal form. In fraction form you could reduce 6 and 4 and make the six a 3 and make the four a 2. Then multiply it out. Which would be 3/1 multiplied by 7/2 = 21/2

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3 years ago

What does it mean for a differential equation to be autonomous?

andrew11 [14]

The term "autonomous" refers to an ordinary differential equation that relates the derivatives of the dependent variable as a function *only* of the dependent variable. In other words, the ODE doesn't explicitly depend on the independent variable.

Examples:

$y'=y^2-1$ is autonomous

$y'=y^2-1+x$ is *not* autonomous

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3 years ago

The table below shows the outputs y for different inputs x:

igor_vitrenko [27]

Part A)
The table doesn't represent y as a function of x.
Why? <span>One reason is that 1 or 3 is the first element in more than one ordered pair.
Part B)
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3 0

3 years ago

Read 2 more answers

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Show Work Please Thank You

Damm [24]

The angles in degrees to radian is as follows:

-54 degrees = -3π / 10 radian

<h3>How to convert from degree to radian?</h3>

The measurement is in degrees. Let's convert it to radian with respect to π.

Therefore,

180 degrees = π radian

-54 degrees = ?

cross multiply

Hence,

angle in radian = -54 × π / 180

angle in radian = - 54π / 180

angle in radian = - 6π / 20

angle in radian = -3π / 10 radian

learn more on radian here: brainly.com/question/22212006

#SPJ1

3 0

1 year ago