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butalik [34]
3 years ago
12

Pls help me thanks!!

Mathematics
2 answers:
Leni [432]3 years ago
3 0

Answer:

Its A <3

Step-by-step explanation:

Murrr4er [49]3 years ago
3 0

Answer:

point B :P

Step-by-step explanation:

dont take my word i just guessed LOL

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Ted rented a bike from Pranav’s bikes. It cost $10 plus $5 per hour. If ted paid $50 then he rented the bike for how much many h
-Dominant- [34]
Ted rented the bike for 8 hours

cost of Bike $10

50-10=40

40/5, (because each hour costs $5)=8
7 0
3 years ago
Read 2 more answers
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a
Julli [10]

Answer:

quantity a is halfed

Corrected question;

A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?

Step-by-step explanation:

Analysing the question;

A quantity a varies inversely as a quantity b,

a ∝ 1/b

a = k/b ......1

when b changes a changes in the inverse ratio;

Since the change at the same ratio but inversely, k = 1

So, equation 1 becomes;

a = 1/b

If the quantity b doubles,

ab = 1

a1b1 = a2b2

When b doubles, b2 = 2b1

a1b1 = a2(2b1)

Making a2 the subject of formula;

a2 = a1b1/(2b1)

a2 = a1/2

Therefore, when b doubles, a will be divided by 2, that means a is halfed.

3 0
3 years ago
if you multply two decimals that are less than 1 , can you predict whether the product will be less than or greater than either
nekit [7.7K]
Yes.  Multiplying anything by a number less than one will decrease the original number.  So multiplying two decimals will result in a number less than either one.
7 0
3 years ago
What is a rational number
irinina [24]
A number that can be turned into a ratio form.
5 0
3 years ago
Read 2 more answers
Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8
san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}

Firstly, we will factor both denominators

b^2-64=b^2-8^2=(b-8)(b+8)

b^2+7b-8=(b+8)(b-1)

so, we can plug it back

\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}

First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

LCD=(x-8)(x+8)(x-1)


3 0
3 years ago
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