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butalik [34]
3 years ago
12

Pls help me thanks!!

Mathematics
2 answers:
Leni [432]3 years ago
3 0

Answer:

Its A <3

Step-by-step explanation:

Murrr4er [49]3 years ago
3 0

Answer:

point B :P

Step-by-step explanation:

dont take my word i just guessed LOL

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Suppose the population of a town is 8,200 and is growing 4% each year, what is the population expected to be in 10 years
miv72 [106K]

Answer:

12,138 people

Step-by-step explanation:

Create an equation using the basic exponential growth equation:

y = a(1 + r)^t, where a is the initial amount, r is the growth rate as a decimal, and t is the amount of time in years.

Plug in the values we know

y = a(1 + r)^t

y = 8200(1 + 0.04)^10

y = 8200(1.04)^10

= 12,138 people

8 0
3 years ago
How can i simplify 16m cubed -10m squared
adoni [48]
16m cubed - 10m squared......
take out the common factors
they both have a two that can go into it and both have two m's you can take out
so then it becomes
2m squared(8m-5) and thats your answer (:
5 0
3 years ago
Read 2 more answers
2. Find the product of each of the following:
Kruka [31]

Step-by-step explanation:

i) \:  \frac{3}{5}  \times (   \frac{ - 7}{8} ) =  -  \frac{21}{40}  \\  \\ ii) \:  \frac{ - 9}{2}  \times  \frac{5}{4}  =   - \frac{45}{8}  \\  \\ iii) \:  \frac{ - 6}{11}  \times  \frac{5}{3}  =  -  \frac{10}{11}  \\  \\ iv) \:  \frac{ - 2}{3}   \times  \frac{6}{7}  =  -  \frac{4}{7}  \\

6 0
3 years ago
All of the following represent the same function except ____.
Whitepunk [10]

Answer:

I believe it's C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
2 years ago
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