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s344n2d4d5 [400]

3 years ago

14

Cos("*) = O A. V3 2 O B. 13 2 C. 1 D. NI

1 answer:

Vitek1552 [10]3 years ago

6 0

$\purple{ \huge{ \tt \: Answer : }}$

<h2> $\: \: \: \: \: \: \: \red{ \boxed{ \boxed{ \sf{{ \: - \frac{ \sqrt{3} }{2} \: \: }}}}}$ </h2>

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Solve using the Pythagorean identity<br>

Lynna [10]

<h3> $\bold{Sin\theta_{1}=-\frac{4}{5}}$ </h3>

Answer:

Solution given

Cos $\displaystyle \theta_{1}=\frac{3}{5}$

consider Pythagorean theorem

$\bold{Sin²\theta+Cos²\theta=1}$

Subtracting $Cos²\theta$ both side

$\displaystyle Sin²\theta=1-Cos²\theta$

doing square root on both side we get

$Sin\theta=\sqrt{1-Cos²\theta}$

Similarly

$Sin\theta_{1}=\sqrt{1-Cos²\theta_{1}}$

Substituting value of $Cos\theta_{1}$

we get

$Sin\theta_{1}=\sqrt{1-(\frac{3}{5})²}$

<h3>Solving numerical</h3>

$Sin\theta_{1}=\sqrt{1-(\frac{9}{25})}$

$Sin\theta_{1}=\sqrt{\frac{16}{225}}$

$Sin\theta_{1}=\frac{\sqrt{2*2*2*2}}{\sqrt{5*5}}$

$Sin\theta_{1}=\frac{4}{5}$

Since

In IVquadrant sin angle is negative

$\bold{Sin\theta_{1}=-\frac{4}{5}}$

7 0

3 years ago

Read 2 more answers

Reduced to lowest terms.<br> 44 nickels to 11 dimes

Finger [1]

Answer:

4 nickels to 1 dime

Step-by-step explanation:

the steps are in the pic above I gotta get this to 20 characters bye!

3 0

3 years ago

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Number 23 I have no clue

kipiarov [429]

B. Write an equation

7 0

3 years ago

Which expression is a factor of the quadratic 6x^2-11x-35?<br><br> 2x-7, 2x-5, 2x+7, 2x+5

vovangra [49]

1. Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

8 0

3 years ago

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two sides of a triangle have the same length. the third side measures 6 m less than twice the common length. the perimeter of th

Y_Kistochka [10]

Let $x$ be the length of the two sides that are the same.

Then the third side would be $2x -3$ .

The perimeter of the triangle will come from adding all of the sides together and setting it equal to the value given, $13$ .

That is,

$x + x + (2x - 3) = 13$

$-- > 4x - 3 =13$

$-- > 4x = 16$

$-- > x = 4.$

As for the answer, the question was cut short, but with $x=4,$ ,

the length of each of the common sides is $4$ , making the third side $5$ , to get a total perimeter of $13$ .

<h3>What are two sides of a triangle?</h3>

The hypotenuse of a right-angled triangle is its longest side, the base is its lower side, and the perpendicular, which stands next to the right angle, is its standing line.

You may determine the sides of a right-angled triangle using a number of techniques, such as the Pythagoras theorem or the triangle's perimeter.

To learn more about sides of a triangle visit:

brainly.com/question/16986516

#SPJ4

5 0

2 years ago