1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
12345 [234]
3 years ago
13

A warehouse is 55 yards long, 35 yards wide, and 5 yards high. What is the area of the warehouse floor? If the warehouse is fill

ed to half it's height with tightly packed boxes, what is the volume of the boxes?
Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

Step-by-step explanation:

First we have to calculate the area, for this we must multiply the length by the width

a = area

l = long = 55yd

w = width = 35yd

a = l * w

a = 55yd * 35yd

a = 1925yd²

to calculate the volume we have to multiply the area by the height

asks us for the volume for half the height so we have to divide the height by 2

a = area = 1925yd²

h = height = 5yd/2 = 2.5yd

v = volume

v = a * h

v = 1925yd² * 2.5yd

v = 4812.5yd³

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

You might be interested in
70% of kids who visit a doctor have a fever, and 40% of kids who visit a doctor have a sore throat. If the probability that a ki
krek1111 [17]

Answer:

52.5%

Step-by-step explanation:

Let A be kids who have a fever, and B be kids who have a sore throat, so

Based on the given information we have

P(A) = 70%, P(B) = 40%, and P(B|A) = 30%   (B|A is read as "B given A", which means probability of B happening given that A has already happened)

We are asked to find P(A|B), the probability of a kid having a fever given that we already know he has a sore throat.

Step 1:  First find P(A and B), this is the probability of a kid having both a fever and a sore throat.  We use the formula

        P(B|A) = P(A and B)/P(A)    

We have 2 of these values listed above, so we plug them in...

       30% = P(A and B)/70%

 This give us a value for P(A and B) which equals 21%  [multiply both sides by 70% to isolate P(A and B), (30%)(70%) = 21%]

Now we flip the equation to P(A|B), which is

     P(A|B) = P(A and B)/P(B)

We have 2 of the values, so we plug them in...

     P(A|B) =  21%/40%

  This gives us a value of 52.5%   (divide 21% by 40%)  

6 0
3 years ago
Plz do have mercy and help me
Nikitich [7]
I have mercy:

8x and 9x+5 (the angles) form a right angle so 8x+9x+5=90 which means x is 5 and plugging it back into the angles 8x we get 40 sinceBHR and angle 8x are vertical angles they are equal to each other and so it's equal to 40
4 0
3 years ago
What is the percentage change in total number of players from Tram A 2021 to 2022 when more than 6 but less 20 matches where won
babunello [35]

Answer:

46%

Step-by-step explanation:

You subtract the old by new then devide by the old and multiply by 100%

8 0
2 years ago
21. Who is closer to Cameron? Explain.
pickupchik [31]

Problem 21

<h3>Answer:  Jamie is closer</h3>

-----------------------

Explanation:

  • A = Arthur's location = (20,35)
  • J = Jamie's location = (45,20)
  • C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer:  Arthur is closest to the ball</h3>

-----------------------

Explanation:

We have these key locations:

  • A = Arthur's location = (20,35)
  • J = Jamie's location = (45,20)
  • C = Cameron's location = (65,40)
  • B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

  • AB
  • JB
  • CB

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

-------------

So in summary, we have these approximate segment lengths

  • AB = 29.1547595
  • JB = 41.2310563
  • CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0
3 years ago
The students have a box that is 12 inches long, 6 inches wide, and 4 inches tall. When
sweet [91]

The volume of the box will be equal to V= 288 cubic inches.

<h3>What is volume?</h3>

Volume is defined as the space occupied by any object in the three-Dimensions. All three parameters are required for the volume like length, width and height of the Cuboid.  

The given parameters of the box are:-

12 inches long

6 inches wide

4 inches tall

So the volume of the box will be:-

V = L  x   W   x   H

V = 12 x  6  x   4

V = 288 square inches

Therefore the volume of the box will be equal to V= 288 cubic inches.

To know more about Volume follow

brainly.com/question/1972490

#SPJ1

8 0
2 years ago
Other questions:
  • 1. ABCD is a trapezoid with midsegment EF. If AB = 12 and CD = 24, what is the length of EF?
    14·2 answers
  • HELP ME ASAP! I NEED TO ADD SOME ONE BRAINLIST!!! WORTH 20 POINTS AND BRAINLIST WHEN U TELL ME!!
    8·2 answers
  • Which expression means the same as 3 x 3/4?
    10·1 answer
  • What is 16tons what pounds
    15·2 answers
  • In this line of ,the ratio of red circles to blue circles is 1:3 , How many more red circles would need to be added to make the
    7·1 answer
  • Can somebody please help me with this question
    11·1 answer
  • Solve rational exponents x2/3=16
    9·2 answers
  • How do I write a expression for the sequence in the table? Answer fasts plzz
    8·1 answer
  • Image not writing all that.
    10·2 answers
  • Find the GCF<br> 34 &amp; 68
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!