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Mars2501 [29]
3 years ago
12

How many times does 7 go into 48

Mathematics
1 answer:
givi [52]3 years ago
4 0
6 times because 6•7=42 so it must be 6 because 7•7=49
Good luck!!
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-1/2x = -7 please answer I need help
Sloan [31]

Answer:

x = 14

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Multiply -2 to both sides of the equation:

-2 * (-1/2x) = -2 * -7

x = -2 * -7

x = 14

Note that when you multiply two negative numbers, the answer will be positive.

14 is your answer for x.

~

3 0
3 years ago
An amount of $18,000 is borrowed for 10 years at 8.25% interest, compounded annually. If the loan is paid in full at the end of
cricket20 [7]
218 dollars will have to be paid back
6 0
3 years ago
Find two consecutive even numbers whose sum is 126
aalyn [17]

Answer:

62+64 = 126

Step-by-step explanation:

If 126/2=63, then 62+64 = 126

3 0
3 years ago
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Hannah is deciding between two truck rental companies. Company A charges an initial fee of $30 for the rental plus $2 per mile d
Degger [83]

Answer:

Hannah is deciding between two truck rental companies. Company A charges an initial fee of $30 for the rental plus $2 per mile driven. Company B charges an initial fee of $100 for the rental plus $1 per mile driven. Let AA represent the amount Company A would charge if Hannah drives xx miles, and let BB represent the amount Company B would charge if Hannah drives xx miles. Write an equation for each situation, in terms of x,x, and determine the interval of miles driven, x,x, for which Company A is cheaper than Company B.

5 0
3 years ago
at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply
katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

We want to find the values of x where the graph will have vertical assymptote.

Vertical asymptotes are defined as vertical lines which correspond to the values of x that will make the denominator of a rational function to be zero.

Thus, to get the values of x that we will have vertical assymptotes, we have to equate the denominator to zero.

We have;

[(x² - 1)(x² -16)] = 0

Thus,

x² - 1 = 0

Or

x² - 16 = 0

So;

x² = 1

x = √1

x = 1

Or

x² = 16

x = ±√16

x = ±4

Values of x that give vertical assymptote are;

x = -4, 1, 4

3 0
3 years ago
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