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anygoal [31]
3 years ago
14

A BluRay disc normally costs $22. This week it is on sale for 25% off the original price. How much money is discounted from the

original price of the BluRay disc?
Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

$7.33

Step-by-step explanation:

22=3/4x

22/.75=22*4/3=29.3333333

$29.33-$22=$7.33

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Which of the following statements are equivalent to the statement "price decreased by one third"?
N76 [4]
75% of what it before
4 0
3 years ago
Sally either walks, cycles or drives to work. She walks about 15% of the time and drives about 3/5 of the time. What percentage
goblinko [34]

Answer: She cycles 25% of the time

Step-by-step explanation:

From the question, Sally walks 15% of the time.

She drives 3/5 of the time.

We then convert 3/5 to percentage.

Converting to percentage means multiplying by a factor of 100.

Hence, Sally drives 3/5*100 = 60% of the time.

If Sally walks 15% of the time and drives 60% of the time, adding up the percentage time used by these two media of transportation will give us

60% + 15% = 75%

Hence if she cycles for the remainder of the time, expressing it as percentage would mean subtracting the time used in other means by 100%

Hence it will be 100% - 75% = 25%

8 0
4 years ago
Which is a net for a cube
sladkih [1.3K]

Answer:

wy m by that??!???? im confused

4 0
3 years ago
For the function given state the period f(t) =6sin(3t-pi/6)-1
lapo4ka [179]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now, with that template in mind, let's take a peek at yours

\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}
8 0
4 years ago
What is the distance between (–13, 9) and (11, 2) on a coordinate grid?
IrinaVladis [17]

Answer:

(13,6)

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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