All categories

3 years ago

Prove that 409 is prime

Mathematics

1 answer:

Pavel [41]3 years ago

5 0

Answer:

A prime number is a natural number, greater than one, that can only be divided by 1 and itself.

The number 409 can be evenly divided by 1 and 409, with no remainder.

Since 409 can only be divided by just 1 and 409, it is a prime number.

hope this helps!

You might be interested in

Find the simple interest on a $2350 principal deposited for six years at a rate of 4.77%

svetlana [45]

$672.57
2350x .0477x6=

7 0

3 years ago

In a topographical map of a city, the vertices of the city limits are A (10, 9), B (18, 9), C (18, 2), D (14, 4.5), and E (10, 4

harkovskaia [24]

Srry don't have answer NEEEEEDDD HELP!!

5 0

3 years ago

The number line diagram shows the distance between each number in a set of ata and the data's mean of 12. Which is the mean abso

Murrr4er [49]

The mean is 12.6 and your welcome

4 0

3 years ago

2х5y-3z-=14 x-2y+=-12 -x+ Зу-2z =13

lukranit [14]

Answer:

x = -34/3, y = 1/3, and z = -35/3

Step-by-step explanation:

2х+5y-3z-=14 let's call this equation 1.

x-2y=-12 let's call this equation 2.

-x+Зу-2z =13 let's call this equation 3.

USING EQUATION 1 AND EQUATION 3.

2х+5y-3z-=14 (EQUATION 1)

-x+Зу-2z =13 (EQUATION 3)

LET'S GET RID OF z, BY MAKING THE COEFFICIENT OF z IN THE TWO EQUATION THE SAME. WE WILL MULTIPLY EQUATION 1 BY 2 AND EQUATION 3 BY 3.

2х+5y-3z-=14 (EQUATION 1) * 2

-x+Зу-2z =13 (EQUATION 3) * 3

4х+10y-6z-=28 let's call this equation 4.

-3x+9у-6z =39 let's call this equation 5.

TO GET RID OF z, WE WILL HAVE TO SUBTRACT EQUATION 5 FROM EQUATION 4 PLEASE TAKE NOTE OF THE SIGNS (-) (+).

4х+10y-6z-=28 (EQUATION 4)

- (-3x+9у-6z =39) (EQUATION 5)

(4x - 3x) + ((+10y) - (+9y)) + ((-6z) - (-6z)) = (28 - 39)

x + y + 0 = -11

x + y = -11 let's call this equation 6.

USING EQUATION 2 AND EQUATION 6, LET'S FIND x AND y.

x-2y=-12 (EQUATION 2)

x + y = -11 (EQUATION 6)

x has the same coefficient in both equations, which is 1. Let's get rid of x so we can find the value of y.

We will subtract equation 6 from equation 2. Take note of the signs.

x-2y=-12 (EQUATION 2)

- (x + y = -11) (EQUATION 6)

(x - x) + ((-2y) - (+y)) = ((-12) - (-11))

0 + -3y = -1

-3y = -1

Divide both sides by -3.

-3y/-3 = -1/-3

y = 1/3

LET'S SUBSTITUTE THE VALUE OF y INTO EQUATION 2 TO GET THE VALUE OF x.

x-2y=-12 (EQUATION 2)

x-2(1/3)=-12

x -2/3 = -12

Add 2/3 to both sides.

x -2/3 + (2/3) = -12 + (2/3)

x + 0 = -34/3

x = -34/3

LET'S SUBSTITUTE THE VALUES OF x and y INTO EQUATION 1 TO GET THE VALUE OF z.

2х+5y-3z-=14 (EQUATION 1)

2(-34/3)+5(1/3)-3z-=14

-68/3 + 5/3 - 3z = 14

-21 - 3z = 14

Add 21 to both sides.

-21 + (21) - 3z = 14 + (21)

0 - 3z = 35

-3z = 35

Divide both sides by -3.

-3z/-3 = 35/-3

z = -35/3 or

Therefore, x = -34/3, y = 1/3, and z = -35/3

Please thank, rate 5 stars, and give brainliest. Thank you.

6 0

3 years ago

Find the coordinates of the midpoint M and the distance between P(-6, -1) and Q(1,2). Round to the nearest

nlexa [21]

Answer:

M(-3.5, 0.5)

Step-by-step explanation:

Given points:

P(-6, -1) and Q(1,2)

Midpoint by using midpoint formula:

x = (-6 + 1)/2 = -3.5
y = (-1 + 2)/2 = 0.5
M(-3.5, 0.5)

4 0

3 years ago