Answer:
2√2
Step-by-step explanation:
We can find the relationship of interest by solving the given equation for A, the mean distance.
<h3>Solve for A</h3>
<h3>Substitute values</h3>
The mean distance of planet X is found in terms of its period to be ...
The mean distance of planet Y can be found using the given relation ...
The mean distance of planet Y is increased from that of planet X by the factor ...
2√2
-x ---------------- 1x
7y --------------- 12y
-12x^2 --------- 8x^2
a ----------------- -2a
6a^2------------ a^2
-5x^3 ---------- 15x^3
_____________________
you just have to match the terms which have the same power.
Hope it helps ^^
Answer:
13.22
Step-by-step explanation:
were solving for t and we know:
a(t)=p(1+(r/n))^nt
5000=a-the total
2940=p-the starting amount
.041=r-the rate
1=n-compound (annual)
plug this into a graph :
5000=2940(1+(.041/1))^x
and you get : 13.22
<h3>
Step-by-step explanation:</h3>
<u>Pythagorus theorum:</u>
9² = 3² + YZ²
81 - 9 = YZ²
√72 = YZ
∴YZ= 8.48 ≈ 8.5
<u>Trigonometry:</u>
We have adjacent as 3, and hypotenuse as 9
cos X = 3/9
X= cos∧-1 (3/9) → <em>[cos inversed]</em>
∴X= 70.5°
We have opposite as 3 and hypotenuse as 9
sin Z= 3/9
Z= sin∧-1 (3/9)→<em> [sin inversed]</em>
∴Z= 19.47 ≈ 19.5
