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ICE Princess25 [194]
3 years ago
12

A blue boat and a red boat are on the same side of a lake and are 18 miles apart. The blue boat is 30 miles from a lighthouse on

the opposite side of the lake. The angle formed by the boats and the lighthouse, and whose vertex is at the blue boat, measures 120°. Find the distance from the red boat to the lighthouse. What is the angle made from the lighthouse to the two boats?
Mathematics
1 answer:
rewona [7]3 years ago
8 0

9514 1404 393

Answer:

  • red boat distance: 42 miles
  • angle at lighthouse: 22°

Step-by-step explanation:

The Law of Cosines can be used to find the distance from the red boat to the lighthouse.

  b² = l² +r² -2lr·cos(B)

  b² = 18² +30² +2·18·30·cos(120°) = 1764

  b = √1764 = 42

The distance from the red boat to the lighthouse is 42 miles.

__

The angle at the lighthouse can be found using the law of sines.

  sin(L)/l = sin(B)/b

  L = arcsin(l/b·sin(B)) = arcsin(18/42·sin(120°)) ≈ 21.79°

The angle between the boats measured at the lighthouse is about 22°.

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3 years ago
Una fábrica produce tres tipos de balones de fútbol, con un costo mensual de
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Answer:

Se fabricaron:

1000 balones de los que cuestan $20

75 balones de los que cuestan $30

50 balones de los que cuestan $40

Step-by-step explanation:

Vamos a definir las variables:

x = número de balones de $100.00 vendidos.

y = número de balones de $120.00 vendidos

z = número de balones de $160,00 vendidos.

Sabemos que se producen 1125 balones, entonces:

x + y + z = 1125

y el costo de producción es $24,250, conociendo el costo de cada balón podemos escribir:

x*$20 + y*$30 + z*$40 = $24,250

Y también sabemos que la ganancia mensual es $92,750

Ganancia es la diferencia entre el dinero total recibido y los costos, entonces:

x*$100 + y*$120 + z*$160 - $24,250 =  $92,750

x*$100 + y*$120 + z*$160 = $92,750 + $24,250

x*$100 + y*$120 + z*$160 = $117,000

Entonces tenemos un sistema de 3 ecuaciones:

x + y + z = 1125

x*$20 + y*$30 + z*$40 = $24,250

x*$100 + y*$120 + z*$160 = $117,000

Para resolver esto debemos comenzar por aislar alguna variable en alguna de las ecuaciones, yo comenzare aislando x en la primera ecuación:

x = 1125 - y - z

Ahora podemos reemplazar esto en las otras dos ecuaciones para obtener:

(1125 - y - z)*$20 + y*$30 + z*$40 = $24,250

(1125 - y - z)*$100 + y*$120 + z*$160 = $117,000

Si simplificamos esto obtenemos:

$22,500 + y*$10 + z*$20 = $24,250

$112,500 + y*$20 + z*$60 =  $117,000

Ahora de vuelta, debemos aislar una variable en una de las ecuaciones, si aislamos y en la primera ecuación obtenemos:

y*$10 = $24,250 - $22,500 -  z*$20

y = ($1,750 - z*$20)/$10

y = 175 - 2*z

Reemplazando esto en la otra ecuación obtenemos:

$112,500 + (175 - 2*z)*$20 + z*$60 =  $117,000

Ahora podemos resolver esto para z.

(175 - 2*z)*$20 + z*$60 =  $117,000 - $112,500

(175 - 2*z)*$20 + z*$60 = $4,500

$3,500 - z*$40 + z*$60 = $4,500

$3,500 + z*$20 = $4,500

z*$20 = $4,500 - $3,500 = $1,000

z = $1,000/$20 = 50

Entonces tenemos 50 balones de los que cuestan $40.

Usando la ecuación y = 175 - 2*z podemos encontrar el valor de y.

y = 175 - 2*50 = 75

Entonces tenemos 75 balones de los que cuestan $30.

Usando la ecuación x = 1125 - y - z podemos encontrar el valor de x.

x = 1125 - 75 - 50 = 1000

tenemos 1000 balones de $20.

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