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Romashka [77]
3 years ago
9

( 2 x 8 ) - ( 2 x 3 ) = __ x ( 8 - 3 )

Mathematics
2 answers:
Airida [17]3 years ago
4 0

Answer:

2

Step-by-step explanation:

katovenus [111]3 years ago
3 0

Answer:

__1__is multiplied by x

so x=2

........

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Need help with a math question
Svetach [21]

Answer:

(x+1)^2+(y-7)^2=8

Step-by-step explanation:

You should try the next one and I can check work or tell you if it is right.  

The diameter length can be found be computing the distance that (-3,5) is to (1,9) which is sqrt(4^2+4^2)=sqrt(32).

The radius is half the diameter so it is sqrt(32)/2.

The center of the circle is the midpoint of a diameter. So compute the (Average of x, average of y)=(-1,7)

So plug into (x-h)^2+(y-k)^2=r^2 we get

(x+1)^2+(y-7)^2=32/4

simplifying gives

(x+1)^2+(y-7)^2=8

(I had to type this twice; my cat jump on my keyboard)

4 0
3 years ago
Read 2 more answers
You are looking at a convention bid that requires 100,000 square feet of meeting space. You have one room at 200 ft x 200 ft, an
Alla [95]
The 2 rooms only add up to 45,000 square feet (150 x 150 x 2) and the larger room is only 40,000 square feet (200 x 200) so this only gives you 85,000 square feet (40,000 + 45,000) which is not enough for the 100,000.
7 0
3 years ago
Alina has just recieved 3 video games for her birthday to add to her existing 12 video games. A week later she went to the thrif
Papessa [141]
Let the existing no. of video games she had be x,
then 
(3+x)+2x+5

3 0
3 years ago
How many terms are in the simplified expression -3x 2 + 2y 2 + 5xy - 2y + 5x 2 - 3y 2
Vilka [71]

there are 6 terms in the simplified expression


4 0
3 years ago
Read 2 more answers
The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product
tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0
4 years ago
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