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Alexeev081 [22]
3 years ago
15

Suppose you pay $3.00 to roll a fair die with the understanding that you will get back $5 (and your wager) for rolling a 5 or a

2, nothing otherwise. What are your expected net winnings, to the nearest cent?
Mathematics
1 answer:
bija089 [108]3 years ago
4 0
Since one dice has 6 numbers
You would have a 2/6 chance or 1/3
You paid $3 so if you rolled both number you would make $10. Then you would have to subtract the cost of $3 from that. So you could win $7. Not sure if you were using on one or 2 dice to roll. You would just count all the numbers on both dice 12. Then you would have a 4 in 12 chance. 4/12 or 1/3 chance.
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Answer:

F = 1.8C +32

F = 86^{\circ}F

Step-by-step explanation:

Represent Celsius with C and Fahrenheit with F.

So, we have:

(C_1,F_1) = (100,212)

(C_2,F_2) = (0,32)

Solving (a): Represent as a linear equation

First, we calculate the slope:

m = \frac{F_2 - F_1}{C_2 - C_1}

This gives:

m = \frac{32 - 212}{0 - 100}

m = \frac{-180}{- 100}

m = 1.8

The linear equation is then calculated using:

F - F_1 = m(C -C_1)

Where

(C_1,F_1) = (100,212)

m = 1.8

F - 212 = 1.8(C -100)

F - 212 = 1.8C -180

Make F the subject

F = 1.8C -180+212

F = 1.8C +32

Solving (b): The value of F when C = 30

Substitute 30 for C in F = 1.8C +32

F = 1.8 * 30 + 32

F = 54 + 32

F = 86

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