Question

Water boils at 100LaTeX: ^\circ∘ Celsius or 212LaTeX: ^\circ∘ Fahrenheit. Water freezes at 0LaTeX: ^\circ∘ Celsius or 32LaTeX: ^\circ∘ Fahrenheit. If the weather forecaster says it will be 30LaTeX: ^\circ∘ Celsius today, write and solve a linear equation to find what Fahrenheit temperature this is.

Answer 1

Answer:

$F = 1.8C +32$

$F = 86^{\circ}F$

Step-by-step explanation:

Represent Celsius with C and Fahrenheit with F.

So, we have:

$(C_1,F_1) = (100,212)$

$(C_2,F_2) = (0,32)$

Solving (a): Represent as a linear equation

First, we calculate the slope:

$m = \frac{F_2 - F_1}{C_2 - C_1}$

This gives:

$m = \frac{32 - 212}{0 - 100}$

$m = \frac{-180}{- 100}$

$m = 1.8$

The linear equation is then calculated using:

$F - F_1 = m(C -C_1)$

Where

$(C_1,F_1) = (100,212)$

$m = 1.8$

$F - 212 = 1.8(C -100)$

$F - 212 = 1.8C -180$

Make F the subject

$F = 1.8C -180+212$

$F = 1.8C +32$

Solving (b): The value of F when C = 30

Substitute 30 for C in $F = 1.8C +32$

$F = 1.8 * 30 + 32$

$F = 54 + 32$

$F = 86$

Answer 2

Answer:

person above me is wrong