Use special right triangle ratios to find the length of the hypotenuse.

The figure shows the graphs of the cost and revenue functions for a company that manufactures and sells small radios. More than

Lyrx [107]

ANSWER

The company must produce and sell more than 700 radios to have a profit.

EXPLANATION

The revenue function is

$R(x)=40x$
and the cost function is

$C(x)=5,600+32x$

The company will break even when total revenue is equal to the total cost.

This implies that,

$40x =5,600+32x$

We group similar terms to get,

$40x - 32x = 5600$

This simplifies to,

$8x = 5600$

Divide both sides by 8 to get,

$x = \frac{5600}{8}$

$x = 700$

The company breaks even by producing and selling 700 radios.

The company must produce and sell more than 700 radios to have a profit.

5 0

3 years ago

A metal strip is being installed around a workbench that is 10 feet long and 4 feet wide. Find how much stripping is needed.

Airida [17]

28ft because you would have to find the perimeter

6 0

3 years ago

In an auditorium, 1/6 of the students are 5th Graders, 1/3 are 4th Graders, and 1/4 of the remaining students are 2nd graders. I

avanturin [10]

1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12

5 0

3 years ago

Integral of 17/(x^3-125)

daser333 [38]

Answer:

17/75 ln│x − 5│− 17/150 ln(x² + 5x + 25) − 17/(5√75) tan⁻¹((2x + 5) / √75) + C

Step-by-step explanation:

∫ 17 / (x³ − 125) dx

= 17 ∫ 1 / (x³ − 125) dx

= 17 ∫ 1 / ((x − 5) (x² + 5x + 25)) dx

Use partial fraction decomposition:

= 17 ∫ [ A / (x − 5) + (Bx + C) / (x² + 5x + 25) ] dx

Use common denominator to find the missing coefficients.

A (x² + 5x + 25) + (Bx + C) (x − 5) = 1

Ax² + 5Ax + 25A + Bx² − 5Bx + Cx − 5C = 1

(A + B) x² + (5A − 5B + C) x + 25A − 5C = 1

Match the coefficients and solve the system of equations.

A + B = 0

5A − 5B + C = 0

25A − 5C = 1

A = 1/75

B = -1/75

C = -2/15

So the integral is:

= 17 ∫ [ 1/75 / (x − 5) + (-1/75 x − 2/15) / (x² + 5x + 25) ] dx

Simplify:

= 17/75 ∫ [ 1 / (x − 5) − (x + 10) / (x² + 5x + 25) ] dx

Factor ½ from the numerator of the second fraction:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 20) / (x² + 5x + 25) ] dx

Split the fraction:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − ½ (15) / (x² + 5x + 25) ] dx

Multiply the last fraction by 4/4:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − 30 / (4x² + 20x + 100) ] dx

Complete the square:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − 15 / ((2x + 5)² + 75) ] dx

Split the integral:

= 17/75 ∫ 1 / (x − 5) dx − 17/150 ∫ (2x + 5) / (x² + 5x + 25) dx − 17/5 ∫ 1 / ((2x + 5)² + 75) dx

The first integral is:

∫ 1 / (x − 5) dx = ln│x − 5│

The second integral is:

∫ (2x + 5) / (x² + 5x + 25) dx = ln(x² + 5x + 25)

The third integral is:

∫ 1 / ((2x + 5)² + 75) dx = 1/√75 tan⁻¹((2x + 5) / √75)

Plug in:

= 17/75 ln│x − 5│− 17/150 ln(x² + 5x + 25) − 17/(5√75) tan⁻¹((2x + 5) / √75) + C

4 0

3 years ago

Y+5<br> ——=0 solve for y<br> X-1

Ira Lisetskai [31]

Answer:

y = -5

Step-by-step explanation:

see the pic for the steps . .

5 0

3 years ago