An additive inverse of a number (x) is a number which when added to x results in being 0.
The given problem is -3 - (-6)
The additive inverse of -6 is 6
-3 -(-6) = -3 + 6 = 3
Communities property: 6-3 = 3
The answer is:
Because -3+6 is an equivalent expression, the answer is 3
Short answer: 2 * sqrt(13)
Remark
There are a number of ways to look at this. I'll pick the easiest.
Step one
Factor 52 until there are no more prime factors to be used.
52 = 2 * 26
52 = 2 * 2 * 13. That's as far as you can go.
Rule
For every 2 equal prime factors, 1 of them can be taken out side of the root sign. The other one disappears.
sqrt(52) = sqrt(2*2* 13) = 2*sqrt(13)
Answer 2sqrt(13) <<<< answer
Complete question:
He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is
a) less than 8 minutes
b) between 8 and 9 minutes
c) less than 7.5 minutes
Answer:
a) 0.0708
b) 0.9291
c) 0.0000
Step-by-step explanation:
Given:
n = 47
u = 8.3 mins
s.d = 1.4 mins
a) Less than 8 minutes:

P(X' < 8) = P(Z< - 1.47)
Using the normal distribution table:
NORMSDIST(-1.47)
= 0.0708
b) between 8 and 9 minutes:
P(8< X' <9) =![[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]](https://tex.z-dn.net/?f=%20%5B%5Cfrac%7B8-8.3%7D%7B1.4%2F%20%5Csqrt%7B47%7D%7D%3C%20%5Cfrac%7BX%27-u%7D%7Bs.d%2F%20%5Csqrt%7Bn%7D%7D%20%3C%20%5Cfrac%7B9-8.3%7D%7B1.4%2F%20%5Csqrt%7B47%7D%7D%5D)
= P(-1.47 <Z< 6.366)
= P( Z< 6.366) - P(Z< -1.47)
Using normal distribution table,

0.9999 - 0.0708
= 0.9291
c) Less than 7.5 minutes:
P(X'<7.5) = ![P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]](https://tex.z-dn.net/?f=%20P%20%5BZ%3C%20%5Cfrac%7B7.5-8.3%7D%7B1.4%2F%20%5Csqrt%7B47%7D%7D%5D%20)
P(X' < 7.5) = P(Z< -3.92)
NORMSDIST (-3.92)
= 0.0000
If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5
1st trip- $115
And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5
2nd trip- $115
To find out the total of both trips youd add 115+115/
In total, for both trips it will cost $230 dollars.