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Rama09 [41]
3 years ago
5

PLEASE HELP ME

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0
I believe it’s A .....
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Calculate the mean, median, mode, and midrange of this quiz distribution and explain whether the distribution is skewed to the l
Inessa [10]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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Terrence opens a savings account with a deposit of $1000. After 1 year he receives $50 in interest. What is the annual interest
geniusboy [140]

Answer:

Step-by-step explanation:

So, I'm pretty sure this is a problem about compound interest.

The formula for compound interest is A = p(1 + r/n)^nt

For this problem, $1000 is p, the initial amount; A is the total amount, or $1050.

What the problem is asking for is r, the interest rate, which is divided by n. N is the number of times the interest rate is compounded per year; Since the question is asking for the annual interest rate, N would be equal to 1. And because Terrence is has only left his money in for a year, t would also be equal to one.

So, by filling in the formula some, we get this:

$1050 = $1000(1 + r/1)^1*1

To find r, we would need to isolate it in the problem.

1. First, distribute $1000 to the parenthesis(keep in mind that 1000, is also equal to 1000/1:

1050 = (1000 + 1000r/1)^1

2. Then subtract 1000 from both sides:

50 = (1000r/1)^1

3. Multiple both sides by one:

50 = (1000r)^1

4. Divide both sides by 1000:

.05 = r^1 or .05 = r.

The answer is A, 5%.

8 0
4 years ago
Kim scored 33 points at her basketball game game with a combination of 2-point shots and 3-point shots. If she made a total of 1
Rudik [331]

Answer:

(12, 3)

Step-by-step explanation:

write the equation:

if x = number of 2 point shots

and y = number of 3 point shots

2x + 3y = 33

write another equation with the total baskets

x + y = 15

plug them both into desmos and find the solution

(12, 3)

she made 12 2-point shots and 3 3-point shots

3 0
3 years ago
Read 2 more answers
PLEASE HELPP WILL MARKDOWN BRAINLIEST!!
Nastasia [14]

Answer:

it has infinite solutions because the lines wont end.

Step-by-step explanation:

6 0
3 years ago
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What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
3 years ago
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