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kozerog [31]
4 years ago
6

Knoll, inc. currently sells 15,000 units a month for $50 each, has variable costs of $20 per unit, and fixed costs of $300,000.

knoll is considering increasing the price of its units to $60 per unit. if the price is changed, how many units will knoll need to sell for profit to remain the same as before the price change?
Business
1 answer:
Lunna [17]4 years ago
3 0
Cost per unit
(300,000÷15,000)+20=40

Current profit
50×15,000−40×15,000=150,000

Profit change
60×15,000−40×15,000=300,000

units will knoll need to sell for profit to remain the same as before the price change is
(150,000+300,000)÷40=11,250
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Seven years ago, Carlos took out a 30-year mortgage for $185,000 at 5.6 percent. He has made all of the monthly payments as agre
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Answer:

Remaining balance of loan after 7 years ( today ) = $ 164,619.6

Explanation:

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original term of loan 30 years * 12 = 360 months

interest rate = 5.6 % * 1/12 =0.4666% per month

monthly payment = amount oa mortgage * i /[ 1- (1+i)^-n ]

= $ 185,000 * 0.4666% / [ 1- ( 1 +0.4666%)^-360 ]

= $ 863.21 / [ 1 - 0.187148 ]

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remaining balance of loan after 7 years ( 84 months ) = [ $ 185,000 * ( 1+0.4666%)^84 ] - $ 1061.95 * [ {(1+0.4666%)^84 - 1} / 0.4666 ]

= [ $ 185,000 * 1.47850 ] - $ 1061.95 * ( 0.47850 / 0.4666% ]

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The fewest number of hours from the graph is 73 hours.

<h3>Equation</h3>

Equation is an expression used to show the relationship between two or more numbers and variables.

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The fewest number is (20, 53)

The fewest number of hours from the graph is 73 hours.

Find out more on equation at: brainly.com/question/2972832

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