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Misha Larkins [42]
3 years ago
8

HELP ME PLEASEEEEEEEEEEEEEEEEE

Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0

Answer:

x

Step-by-step explanation:

f(f^{-1}(x))

Lets work the brackets first!

f^{-1}(x)

To solve we are going to find the inverse of the function.

f^{-1}(x)

f ⇔ y

∴ y = x

Interchange x and y

x = y

Solve for y

y = x

∴ f^{-1}(x) = x

Now let's solve the rest of the equation.

f(x) = x

∴ f(f^{-1}(x)) = x

katrin2010 [14]3 years ago
6 0
The answer is just x
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Please check attached vertical number line.

(a) The temperature differences are listed below:


Between Cities                            Temperature difference


Smithton and

Hedgeburough                                  2.5 - (-1.1) = 2.5 + 1.1 = 3.6


Hedgeburough and

East Bunting                                       - 1.1 - (- 0.5) = - 1.1 + 0.5 = -0.6


East Bunting and

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7 0
3 years ago
Read 2 more answers
Solve for z.<br> -30 = 5(x+1)
melisa1 [442]
-30= 5 (x+1 )

-5 from 5= 0
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6 0
2 years ago
June had $240 more than Siti. Junr gave 25% of her money to Siti. Siti then gave 20% of her money to June. How much more money d
bulgar [2K]

Answer:

$144

Step-by-step explanation:

Let the money which Siti has be x

Therefore, the money June has will be x+240

First condition is that June gave 25% of her money to Siti, So this amount will be deducted from June's money and will be added in Siti's money.

Siti's money = x+ [25%(x+240)]       June's money = x+240-[25%(x+240)]

                   = 1.25x + 60                                       = 0.75x + 180

Second condition is that Siti now gave 20% of her money to June.This amount will be deducted form Siti's money and added in June's money.

Siti's money = 1.25x+60-[20%(1.25x+60)]    

                    = x+48

June's money = 0.75x +180+[20%(1.25x+60)]

                        = x+192

Difference between Sitit and June's money = x+192-x-48

                                                                        = 144

Hence, June has $144 more money than Siti.

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What are simultaneous equations​
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Answer:

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