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Ilya [14]
3 years ago
15

NEED HELP RIGHT NOW PLEASEE!!

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer

if i am coorect both of them are 180 hope this helps

Step-by-step explanation:

denpristay [2]3 years ago
4 0
Yess 180 ! Is the correct answer
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Use the given information to find the ​p-value. ​Also, use a 0.05 significance level and state the conclusion about the null hyp
faltersainse [42]

Answer:

p_v =P(z>1.34)=1-P(z  

Step-by-step explanation:

1) Data given and notation n  

n represent the random sample taken

Xrepresent the people with a characterisitc in the sample

\hat p estimated proportion of people with the characteristic desired

p_o=0.554 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the population proportionis higher than 0.554.:  

Null hypothesis:p\leq 0.554  

Alternative hypothesis:p > 0.554  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

The value of the statisitc is already calculate and given:  

z=1.34  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one right tailed test the p value would be:  

p_v =P(z>1.34)=1-P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we don't have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.554 .  

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3 years ago
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