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ch4aika [34]
2 years ago
13

What is the length of BC?

Mathematics
2 answers:
Ber [7]2 years ago
7 0

Answer:

the length is 4

Step-by-step explanation:

12-8 =4

hope it helps

makvit [3.9K]2 years ago
7 0
The answer is 4, BC=4. If you take 12-8 you get 4
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Which face has an area of 28 cm
Neko [114]

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trapezium?

Step-by-step explanation:

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3 years ago
Wht is the substitution of x+y=9 and x=2y
Rama09 [41]
I hope this helps you



2y+y=9



3y=9



y=3


x=2y=2.3=6
3 0
3 years ago
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saveliy_v [14]

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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3
Sliva [168]

Answer:

i) it is not possible for the student to receive an A in the class

ii) 119 points

iii) 84points

Step-by-step explanation:

Total exam scores = 350points

homework scores of 7, 8, 7, 5, and 8

Let the third exam score =y

Exam scores = 81, 80, x

i) To know if the student would get an A in class, we would find the third exam score

(Scores received by a student)/ (total scores) = least of the grade percentage to get an A

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.9

(196+x)/350 = 0.9

196+x = 350 × 0.9

196+x = 315

x = 315-196

x = 119

119 > 100

Since the maximum grade for each of the exam score is 100points, it is not possible for the student to receive an A in the class.

ii) Since the least of the grade percentage that would guarantee an A is 0.9, the minimum score on the third exam that will give an A = 119points

iii) (Scores received by a student)/ (total scores) = least of the grade percentage to get a B

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.8

(196+x)/350 = 0.8

196+x = 350 × 0.8 = 280

x = 280-196

x = 84

The minimum score on the third exam that will give a B = 84points

3 0
3 years ago
What is the distance from Cto D?
IRINA_888 [86]

Given:

The two points C(2,-1) and D(5,3) on a coordinate plane.

To find:

The distance from C to D.

Solution:

The distance between two points is defined by the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The two points are C(2,-1) and D(5,3). Using the distance formula, we get

CD=\sqrt{(5-2)^2+(3-(-1))^2}

CD=\sqrt{(3)^2+(3+1)^2}

CD=\sqrt{(3)^2+4^2}

On further simplification, we get

CD=\sqrt{9+16}

CD=\sqrt{25}

CD=5

The distance from point C to D is 5 units. Therefore, the correct option is A.

8 0
2 years ago
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