Answer:
The length of the rectangle is 12cm and the area of the rectangle is 60cm2.
Explanation:
By definition, the angles of a rectangle are right. Therefore, drawing a diagonal creates two congruent right triangles. The diagonal of the rectangle is the hypotenuse of the right triangle. The sides of the rectangle are the legs of the right triangle. We can use the Pythagorean Theorem to find the unknown side of the right triangle, which is also the unknown length of the rectangle.
Recall that the Pythagorean Theorem states that the sun of the squares of the legs of a right triangle is equal to the square of the hypotenuse. a2+b2=c2
52+b2=132
25+b2=169
25−25+b2=169−25
b2=144
√b2=√144
b=±12
Since the length of the side is a measured distance, the negative root is not a reasonable result. So the length of the rectangle is 12 cm.
The area of a rectangle is given by multiplying the width by the length.
A=(5cm)(12cm)
A=60cm2
Answer:
I think it's number 5 or (5,8)
Step-by-step explanation:
Make a horizontal line on the paper. You may draw arrows on the ends of the line to indicate it is a number line that continues past your data sample.
Put the label "X" to the right of the line to indicate the x axis.
Mark the center of the line with a vertical tick mark and label it 0. This is the origin of the graph.
Make equally spaced tick marks on the rest of the x axis. For this example you should label the tick marks from 1 to 10 on the right side of the 0.
72/100=72%=0.72
Plants survived divided by total plants.
Answer:
The fraction of the total number of leaves did they collect altogether is 
Step-by-step explanation:
This question can be solved by a sum of fractions.
Lee collect 24/100 of the tiral number of leaves needed.
Maya collects 4/10 of the total number of leaves needed.
What fraction of the total number of leaves did they collect altogether?
This is the sum of 24/100 and 4/10.
The lesser common multiple between 100 and 10 is 100. So
We can simplify by four
The fraction of the total number of leaves did they collect altogether is
