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OlgaM077 [116]
3 years ago
9

If x equals 7. What is 3x-47

Mathematics
2 answers:
miskamm [114]3 years ago
7 0

Answer: x = -26

Step-by-step explanation:

3x-47

substitute x with 7: 3(7)-47

3(7) = 21 -47 = -26

kicyunya [14]3 years ago
7 0

Answer:

<u><em>-26</em></u>

Step-by-step explanation:

x=7

3 is being multiplied by X

replace X with 7 in your equation

Your equation should then look like this: 3(7)-47

The parentheses around the 7 indicate that the 7 is being multiplied by the 3 or in other words: (3*7)-47

multiply 3 and seven before subtracting 47

3*7= 21

Once you have your answer to that subtract 47, your answer should be a negative # because you are subtracting a larger # from a smaller #

21-47= -26

so if X equals 7.  3x-47= -26

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Answer:

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Step-by-step explanation:

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Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =
dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

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Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27­°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

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3 years ago
if your watch loses 5 minutes each hour and you set the time correctly at 7.00, what is the actual time when your watch shows la
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From the given the option moved left 1 unit; reflected across the x axis is the correct.

what is function?

A function from a set X to a set Y in mathematics assigns each element of X exactly one element of Y. The set X is known as the function's domain, and the set Y is known as the function's codomain.

We have to describe the position of the function f(x) = -2^x^+^1 relative to the basic function 2^x.

Let the parent function is 2^x.

After shifting one unit right it becomes, 2^x^+^1.

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