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omeli [17]
3 years ago
7

Tell whether the angles are adjacent or vertical. Then find the value of x . 117° xº ​

Mathematics
1 answer:
Yakvenalex [24]3 years ago
5 0

Answer:

please give the picture

Step-by-step explanation:

I will then solve this

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1) Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week.
nignag [31]

1 )  Billy walks 15 miles every day to soccer practice and he had 5 practices last week.

We know that,  1 mile = 1760 yards

So, 15 miles = (15× 1760) yards = 26400 yards

Thus the total distance walked in 5 practices will be: (26400*5)yards = 132000 yards


2) Mark's current age is t years

So, his age was in 10 years ago =(t-10)years

Given that, his current age is 3 times his age 10 years ago.

So, the equation to represent this situation will be :  t= 3(t-10)


3 0
3 years ago
The difference of a number and 6 is the same as 5 times the sum of the number and 2. What is the number?
Sunny_sXe [5.5K]

Answer:.OA. -4

Step-by-step explanation:

4 0
3 years ago
Make COS the subject of the formula
docker41 [41]

c^2 = a^2 + b^2 - 2(ab)(cos C)

c^2 + 2(ab)(cos C) = a^2 + b^2

2(ab)(cos C) = a^2 + b^2 - c^2

cos C = (a^2 + b^2 - c^2) / 2ab - Answer choice E

Hope this helps! :)

6 0
3 years ago
What is the answer to question 41
Nina [5.8K]

Answer:

an = 6 +5(n-1)

an = 1 +5n

Step-by-step explanation:

The equation for an arithmetic term is

an =a1 +d(n-1)

where a1 is the 1st term and d is the common difference

an = 6 +5(n-1)

We can distribute the 5

an = 6+5n-5

an = 1 +5n

4 0
3 years ago
Find the nth degree polynomial function with real coefficients satisfying the given conditions.
RUDIKE [14]
\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------

\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60
4 0
3 years ago
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