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coldgirl [10]
2 years ago
8

WHO IS PUMPED FOR...CHRISTMAS

Mathematics
2 answers:
MA_775_DIABLO [31]2 years ago
4 0
I am very much excited
iren [92.7K]2 years ago
4 0
Christmas was two days ago-

mark me brainliest if possible though, thank you in advance :)
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Brainliest for best answer
pickupchik [31]

Answer:

1. 120, 2. 6, 3. 21

Step-by-step explanation:

7 0
3 years ago
I need this answer as fast as i can get it
Stella [2.4K]

Answer:

Try B. I believe that is the answer

Explanation:

4 0
3 years ago
Read 2 more answers
A worker on the production line is paid a base salary of ​$230.00 per week plus ​$0.78 for each unit produced. Write an equation
iogann1982 [59]

(a)

We are given

A worker on the production line is paid a base salary of ​$230.00 per week

so, base salary =230

Let's assume number pencils produced as x

plus ​$0.78 for each unit produced

now, we can find equation for earnings

E(x)=230+0.78x

now, we are given

her earnings of ​$446.84 for a week when she produced x units

so, we can set E(x)=446.84

and then we can solve for x

446.84=230+0.78x

230\cdot \:100+0.78x\cdot \:100=446.84\cdot \:100

23000+78x=44684

23000+78x-23000=44684-23000

78x=21684

\frac{78x}{78}=\frac{21684}{78}

x=278

so, number of pencils = 278........Answer

(b)

If the worker had produced twice that number of​ units

so, number of pencils =2*278=556

now, we can find earnings

E(x)=230+0.78x

now, we can plug x=556

E(556)=230+0.78*556

E(556)=663.68.................Answer


3 0
3 years ago
Please help asap (:
Korolek [52]
For this case we first define the variable:
 x = number of terms.
 The equation that models the problem is:
 f (x) = 3.4 - 0.6x
 We have then that the first four terms are:
 x = 1
 f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
 x = 2
 f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
 x = 3
 f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
 x = 4
 f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
 Answer:
 
The rule for the sequence is:
 
f (x) = 3.4 - 0.6x
 option 1
7 0
3 years ago
Read 2 more answers
What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
IrinaK [193]
Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)

We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):

Thus,

Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

Therefore, 

log of 1/2 (w^4 u^2 / v^3)

and for the final step and answer, reorder or rearrange w^4 and u^2:

log of 1/2 (u^2 w^4 / v^3)  
8 0
3 years ago
Read 2 more answers
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