Answer:
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(str(year) + " - leap year")
else:
print(str(year) +" - not a leap year")
else:
print(str(year) + " - leap year")
else:
print(str(year) + "- not a leap year")
Explanation:
*The code is in Python.
Ask the user to enter a year
Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times
The five different windows password policies are:
1. Enforce password history.
2. Minimum password length.
3. Minimum password age.
4. Maximum password age.
5. Password must meet complexity requirements. (contain symbols, numbers, letters,...)
