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3 years ago

Please help with these pre-calc questions im so lost

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer: Question #1 B, Question #2 A: 9, –9, and Question #3 (a) A, (b) x–(1/2, 1/3, –7)= 0, and (c) 0?

Step-by-step explanation:

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3 years ago

In Image:

iris [78.8K]

Answer:

The answer to your question is x ≠ -10 x ≠ 2 x ≠ -2

Solution $\frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}$

Step-by-step explanation:

Process

1.- Factor all the polynomials

$\frac{x^{2} -3x - 40}{x^{2} + 8x - 20} / \frac{x^{2}+ 13x + 40}{x^{2}+ 12x + 20}$ = $\frac{(x-8)(x + 5)}{(x + 10)(x- 2)} / \frac{(x+ 8)(x + 5)}{(x + 10)(x + 2)}$

2.- Invert the second term

= $\frac{(x- 8)(x + 5)}{(x +10)(x - 2)} \frac{(x+ 10)(x + 2)}{(x + 8)(x +5)}$

3.- Simplify

= $\frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}$

4.- x must be different to

x ≠ -10 x ≠ 2 x ≠ -2

This values are from the factor expressions and then equal to zero.

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