2 years ago

Please help with these pre-calc questions im so lost

Mathematics

1 answer:

mel-nik [20]2 years ago

6 0

Answer: Question #1 B, Question #2 A: 9, –9, and Question #3 (a) A, (b) x–(1/2, 1/3, –7)= 0, and (c) 0?

Step-by-step explanation:

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Help please asap i will give brainlist

Crazy boy [7]

Answer: If the side which lies on one ray of the angle is longer than the other side, and the other side is greater than the minimum distance needed to create a triangle, the two triangles will not necessarily be congruent. to "swing" to either side of point G, creating two non-congruent triangles using SSA.

Step-by-step explanation:

Here is one of them. I will give the other guy to give you the other one.

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2 years ago

Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2

Savatey [412]

$\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}$