3 years ago

I need help pls if you can’t see let me know

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

4 0

Answer:

I cant see it

Step-by-step explanation:

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Alenkasestr [34]

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G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

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Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

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$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

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