2 years ago

Help with math question please

Mathematics

1 answer:

SashulF [63]2 years ago

5 0

The answer would be a

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Answer:

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Step-by-step explanation:

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5. (Hint: Be sure to know what exactly you are expected to compute.) *

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Step-by-step explanation:

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2 years ago

Anyone in 10th grade please help me because I have to pass this later at 10 pm:(

Alenkinab [10]

18) $19m^8n^8-\left(4m^5n\right)\left(3m^3n^7\right)$

$=19m^8n^8-4m^5n\cdot \:3m^3n^7$

$=19m^8n^8-12m^8n^8$

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19) $\left(-5cd\right)\left(-3c^4d\right)-\left(7c^2d^2\right)\left(2c^3\right)$

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2 years ago

Which are equivalent to Two and three-fourths times eight-ninths? Check all that apply.

stira [4]

Answer: Eleven Fourths xEight Ninths.

Step-by-step explanation: To get the mixed number Eleven Fourths, you have to multiply 4x2 (4 as the denominator and 2 as the whole number) to get 8, and add 3 (numerator) to get 11, and then put 4 over it as the original denominator to get 11/4. Then, just plug back in the numbers: 11/4 x 8/9 (Eleven-Fourths times Eight-Ninths)

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2 years ago

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