Put the numbers in order
6,7,15,36,41,43,47,49
Q1 = (7 + 15) / 2 = 22/2 = 11 <== first quartile
Q2 = (36 + 41) / 2 = 77/2 = 38.5 <== median
Q3 = (43 + 47) / 2 = 90/2 = 45 <== third quartile
difference of largest value and median.....(49 - 38.5) = 10.5
It would be something along the lines of y = p2.75 or p times 2.75
Step-by-step explanation:
![\sqrt{(x + 6) ^{2} } = \sqrt{18} \\ x + 6 = + - \sqrt{18} \\ x + 6 = + - \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28x%20%2B%206%29%20%5E%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B18%7D%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%7B18%7D%20%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%5B3%5D%7B2%7D%20)
Y = -3x + 6....the slope here is -3. A parallel line will have the same slope.
y = mx + b
slope(m) = -3
(-4,7)....x = -4 and y = 7
now we sub into the formula and find b, the y int
7 = -3(-4) + b
7 = 12 + b
7 - 12 = b
-5 = b
so ur parallel equation is : y = -3x - 5 <==
<h3>
Answer:</h3>
A. 28
<h3>
Step-by-step explanation:</h3>
We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA
(5x +3)° = (2x +18)°
Divide by ° and subtract 2x+3:
... 3x = 15
... x = 5
Then ∠BZA = (2·5 +18)° = m = 28°
