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shutvik [7]
3 years ago
10

On a coordinate plane, what is the distance between the points (-1,5) and (2,5)? Enter the answer in the box.

Mathematics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

The distance between (-1,5) and (2,5) is √9 or 3.

Step-by-step explanation:

Okay first, just for explaining purposes, let's call the ordered pair (-1,5) letter A and ordered pair (2,5) letter B.

Now to the answer. To start you use the distance formula. which is:

d=√( (x2-x1)²+(y2-y1)²)

Then you solve by plugging the ordered pairs into the formula where -1 from point A is X1 and 5 from point A is Y1. 2 from point B is X2 and 5 from point B is Y2.

When you solve it should look like this:

1. d=√( (x2-x1)²+(y2-y1)²)

2. d=√( (2- -1)²+(5-5)²) *2 minus a negative one means plus so we get 3*

3.  d=√( (3)²+(0)²)

4. d=√( 9+0)

5. √9 = 3

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Karolina [17]

Answer:

AB is 16 units.

Step-by-step explanation:

Given:

AE = EC

BF = FC

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To Find:

AB = ?

Solution:

Mid Point Theorem:

The Midpoint Theorem states that "the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side".

AE = EC .....Given

Therefore E is the Mid Point of AC.

BF = FC .....Given

Therefore F is the Mid Point of BC.

Therefore,

EF || AB            ........................Mid Point Theorem.

         ..............Mid Point Theorem.

Substituting the values we get

Therefore AB is 16 units.

Step-by-step explanation:

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3 years ago
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4 0
3 years ago
HJ
Olin [163]

Answer:

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

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Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

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x+12 + x-3 = 5x - 6

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-3x = -15

x = -15/-3

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Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

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<IJK = 19 degrees

Hence the measure of <IJK is 19 degrees

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