Answer:
i. ₹5000
ii. ₹105000
iii. ₹5250
iv. ₹110250
Step-by-step explanation:
i.
ii.
iii.
iv.
Answer:
10n + 1n = 11n = 231, and n = 21
Step-by-step explanation:
Let that "same number" be n. Then 10n + 1n = 11n = 231, and n = 21.
Check: Do 21 tens and 21 ones add up to 231?
210 + 21 = 231 ? YES
Answer:
He used to receive $14.50.
Step-by-step explanation:
Let x = amount he used to receive.
Now he receives 2x - 4.
Now he receives $25.
2x - 4 = 25
2x = 29
x = 14.5
Answer: He used to receive $14.50.
The average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12
In this question, we have been given a function g(x)=x^2
We need to find the average rate of change of function on the interval 3 ≤ x ≤ 9
For x = 3,
g(3) = 3^2
g(3) = 9
and for x = 9,
g(9) = 9^2
g(9) = 81
So, the average rate of change would be,
g(9) - g(3) / [9 - 3]
= (81 - 9) / 6
= 72/6
= 12
Therefore, the average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12
Learn more about the average rate of change here:
brainly.com/question/23715190
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