All categories

8 months ago

What is the average rate of change of g(x)=x^2 on the interval 3≤x≤9

Mathematics

1 answer:

Aleks04 [339]8 months ago

6 0

The average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12

In this question, we have been given a function g(x)=x^2

We need to find the average rate of change of function on the interval 3 ≤ x ≤ 9

For x = 3,

g(3) = 3^2

g(3) = 9

and for x = 9,

g(9) = 9^2

g(9) = 81

So, the average rate of change would be,

g(9) - g(3) / [9 - 3]

= (81 - 9) / 6

= 72/6

= 12

Therefore, the average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12

Learn more about the average rate of change here:

brainly.com/question/23715190

#SPJ1

You might be interested in

3^5 * 9^5 = 3^n<br> Find n please

Vladimir [108]

Answer:

In this equation n = 15

Step-by-step explanation:

In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.

3^5 * 9^5 = 3^n

3^5 * (3^2)^5 = 3^n

3^5 * 3^10 = 3^n

3^15 = 3^n

Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n

4 0

2 years ago

What number is greater?

lesantik [10]

10 is greater because it equals 3.162...

3 0

3 years ago

You are making small pizzas. You have 12 cups of flour. Each pizza crust requires 3/

sveticcg [70]

Hello,

The answer is "16".

Reason:

Just divide 12 by 3/4:

12×4=48÷3=16
1×3=3÷3=1

16/1=16

Therefore they can make 16 pizza crusts!

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

3 0

3 years ago

Read 2 more answers

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram