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Greeley [361]
1 year ago
6

What is the average rate of change of g(x)=x^2 on the interval 3≤x≤9

Mathematics
1 answer:
Aleks04 [339]1 year ago
6 0

The average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12

In this question, we have been given a function g(x)=x^2

We need to find the average rate of change of function on the interval 3 ≤ x ≤ 9

For x = 3,

g(3) = 3^2

g(3) = 9

and for x = 9,

g(9) = 9^2

g(9) = 81

So, the average rate of change would be,

g(9) - g(3) / [9 - 3]

= (81 - 9) / 6

= 72/6

= 12

Therefore, the average rate of change of g(x)=x^2 on the interval 3≤x≤9 is 12

Learn more about the average rate of change here:

brainly.com/question/23715190

#SPJ1

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(3x²+3x+5)+(7x²-9x=8)=10x²-12x=13
Brilliant_brown [7]

The value of x is equal to -5/6

To solve this question, we have to add two polynomials together. The polynomials are;

  • 3x^2+3x+5
  • 7x^2-9x=8
<h3>Addition of Polynomials</h3>

This involves adding of two or more different polynomials together. The polynomials adding together are or must be of the same degree. i.e x^2 must add to another coefficient of x^2 and x^3 adds to another coefficient of x^3 and so on.

In this given question, let's add the polynomials together.

(3x^2+3x+5) + (7x^2-9x = 8\)\\3x^2 + 7x^2 + 3x-9x+5-8 =10x^2-6x-3

Now, let's equate this with the last polynomial given

10x^2-6x-3=10x^2-12x-13\\10x^2-10x^2-6x+12x-3+13\\0+12x+10\\12x=-10

Let's solve for x

12x=-10\\x=-\frac{10}{12}\\x = -\frac{5}{6}

The value of x is equal to -5/6

Learn more on addition of polynomials here;

brainly.com/question/4142886

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X/2 = 8

▶ ️2 = 8 × X. (transposing X to RHS )

▶️ 2 = 8X

▶ ️X = 8/2. (transposing 2 to RHS )

▶️ X = 4

hence the value of X is 4.

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