PleaseASAP please I’ll mark you as brainlister

how many 5 letter combinations can be created from the letters in the world “friendly” assume that the order of the letters does

Artyom0805 [142]

Answer:

Number of combinations = 56

Step-by-step explanation:

Points to remember

nCₐ = n!/(r!(n - r)!)

The given word is "FRIENDLY"

F R I E N D L Y is a 8 letter word.

<u>To find the number of combinations</u>

5 letters can be selected from 8 letter = 8C₅

8C₅ = 8!/(8 - 5)!5!

= 8!/3!5!

= (8 * 7 * 6* 5!)/(1 * 2 * 3 * 5!)

= 8 * 7

= 56

5 letter combinations can be created from the letters in the world “friendly = 56

4 0

3 years ago

Help a fellow out please

Liula [17]

Answer:

24.27 cm

Step-by-step explanation:

sin 65 degrees = 22/x, so:

1 x

------------------ = ------

sin 65 deg 22

so x = 22 / (sin 65 deg) = 22/0.906 = 24.27 cm

8 0

3 years ago

The width x of your iris decreases from 4 millimeters to 2 millimeters when you enter a dark room. How many times greater is the

inysia [295]

Answer:

The area of the Iris is 4 times greater.

Step-by-step explanation:

Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!

The average radius of the iris is 6mm, so we take this value.

Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

$6mm-4mm=2mm$

Therefore it's area $A$ is:

$A=\pi r^2=\pi (2)^2=4\pi$

When the iris contracts to 2mm, the radius of the pupil becomes:

$6mm-2mm=4mm$

Then it's area is $A$ :

$A=\pi r^2=\pi (4)^2=16\pi$

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

$\frac{16\pi }{4\pi } =4$

This is 4 times greater than the initial area.

3 0

3 years ago

Can you show all steps to simplify (3x-4)+(x+3)^2

ella [17]

<span>(3x-4)+(x+3)^2
= 3x - 4 + x^2 + 6x + 9 .........(expand using (a+b)^2 = a^2 + 2ab + b^2)
= x^2 + 9x + 5 ..........(combine like terms and simplify)

hope that helps</span>

3 0

3 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$