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PtichkaEL [24]
3 years ago
6

PleaseASAP please I’ll mark you as brainlister

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0

do you need v or u? v= 12.72792206 and u= 18

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Steve sold 36 fruit baskets for a school fundraiser. Evie sold 25% of the number of baskets that Steve sold. How many fruit bask
xeze [42]

Answer:

9 fruit baskets.

Step-by-step explanation:

Given:

Steve sold 36 fruit baskets for a school fundraiser.

Evie sold 25% of the number of baskets that Steve sold.

<u>Question asked:</u>

How many fruit baskets did Evie sell?

Solution:

<u>As given that Evie sold 25% of the number of baskets that Steve sold.</u>

Number of baskets sold by Evie = 25% of 36

                                                      =\frac{25}{100}\times36\\\\  =\frac{900}{100}\\ \\=9

Thus, 9 fruit baskets sold by Evie.

4 0
3 years ago
Solve:<br> -8r - (-2r-3) = 13<br><br> (if you can give a step by step, that would be great!)
coldgirl [10]

Answer:

r =  -  \frac{5}{3}  = 1 \frac{2}{3}  =  - 1.6

Step-by-step explanation:

- 8r -  ( - 2r - 3) = 13

- 8r + 2r + 3 = 13

- 6r + 3 = 13

- 6r = 13 - 3

- 6r = 10

\boxed{\green{r =  -  \frac{5}{3}  = 1 \frac{2}{3}  =  - 1.6}}

4 0
3 years ago
The input-output table shows and values that satisfy the equation Y= 4X +21
Hunter-Best [27]
Answer: 41

Explanation: Use the equation. If you put the x value, which is 5, into the equation, you can solve.

4(5)+21

4 x 5 is 20

20+21=41

hope this helps!!
7 0
3 years ago
Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms con
pav-90 [236]
Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}
6 0
3 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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