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3 years ago

Find the distance between the pair of points (18, -18) and (-17, -25)

Mathematics

1 answer:

MakcuM [25]3 years ago

3 0

Answer:

35.6931366

Step-by-step explanation:

distance = to square root of (x2-x1)^2+(y2-y1)^2

substiute in the equation

so square root of (-17-18)^2+(-25--18)^2

=7square root of 26

or 35.6931366

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Solve the problem and specify the units of measure.

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Answer:

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Step-by-step explanation:

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Olin [163]

Answer:

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Step-by-step explanation:

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Will the gcf of an odd number and a even number is always given

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3 years ago

Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

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3 years ago

1 1

andrey2020 [161]

Answer:

the answer should be 3/10

Step-by-step explanation:

if you look at the photo you can solve it from there

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3 years ago