The numerical value of the mean voltage is 25.47 V
To find the numerical value of the mean voltage, V of V(t) = 40 sin(t), we integrate V(t) with respect to t over the interval [0.π]
So,
![V = \frac{1}{\pi } \int\limits^\pi _0 {V(t)} \, dt \\V = \frac{1}{\pi } \int\limits^\pi _0 {40sint} \, dt \\V = \frac{1}{\pi } [-40cost]_{0}{\pi } \\V = \frac{1}{\pi } -[40cos\pi - 40cos0]\\\\V = \frac{1}{\pi } (-[40 X (-1) - 40 X 1})\\V = -\frac{1}{\pi } [-40 - 40]\\V = \frac{80}{\pi } \\V = 25.465 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7BV%28t%29%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7B40sint%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40cost%5D_%7B0%7D%7B%5Cpi%20%7D%20%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20-%5B40cos%5Cpi%20%20-%2040cos0%5D%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%28-%5B40%20X%20%28-1%29%20-%2040%20X%201%7D%29%5C%5CV%20%3D%20-%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40%20-%2040%5D%5C%5CV%20%3D%20%5Cfrac%7B80%7D%7B%5Cpi%20%7D%20%5C%5CV%20%3D%2025.465%20V)
V ≅ 25.47 V
So, the numerical value of the mean voltage is 25.47 V
Learn more about mean volatage here:
brainly.com/question/17928028
Answer:
y = 3
General Formulas and Concepts:
<u>Algebra I</u>
Coordinate Planes
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
Point (3, 3)
Slope<em> m</em> = 0
<u>Step 2: Find</u>
<em>When the slope is equal to 0, you will have an equation of a horizontal line at a y-coordinate point.</em>
y-coordinate: 3
Equation: y = 3
Hello!
<span>9 - 2 x 3 x 3 + 18
9 - 18 + 18
=9
9 is your answer.
Enjoy.
Brainliest please?
<span>
</span></span>
Answer:
6 * 10^2
Step-by-step explanation:
Simplify : (4.2×10^7)÷(7×10^4)
(4.2 × 10^7) / (7 × 10^4)
From indices : 10^a ÷ 10^b = 10^(a - b)
(4.2 / 7) * 10^(7-4)
0.6 * 10^3
= 6 * 10^2
Hence, (4.2×10^7)÷(7×10^4) = 6 * 10^2
